Solving Force Questions: Mass, Acceleration & Breaking Force

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Homework Help Overview

The discussion revolves around two physics problems: one concerning the time required to stop a car given its mass, speed, and braking force, and the other regarding the tension in a string needed to whirl a stone in a circular path at a specified speed. The subject area includes concepts from dynamics and circular motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the application of Newton's laws and kinematic equations to determine the time to stop the car and the tension in the string. There are questions about unit conversions and the correct interpretation of variables such as velocity and acceleration.

Discussion Status

Some participants have provided guidance on unit conversions and suggested using specific equations related to impulse and momentum. There is an ongoing exploration of the correct approach to both problems, with multiple interpretations being discussed.

Contextual Notes

Participants note the importance of using consistent units (kg, m, s) and question the assumptions made regarding the definitions of velocity and acceleration in the problems.

terpsgirl
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I'm not sure what equation is used on this particular problem.

How much time would be requird to stop a 2,000 kg car that is moving at 80.0 km/hr if the braking force is 8,000 N?

I know...
Mass 2000 kg
Acceleration is 80.0 km/hr
Breaking force is 8,000 N


What tension must a 50.0 cm length of string support in order to whirl an attached 1,000.0 gram stone in a circular path at 5.00 m/s?


I used the formula F= mv^2/ r

= (1,000.0 g) (5.00 m/s)/ 50.0 cm
= 1,000.0 x 5.00 g*m/s
____________________
50.0

I wanted to know if I was tackling this question correctly..if not what am I doing wrong?

THX!
 
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terpsgirl said:
I'm not sure what equation is used on this particular problem.

How much time would be requird to stop a 2,000 kg car that is moving at 80.0 km/hr if the braking force is 8,000 N?

I know...
Mass 2000 kg
Acceleration is 80.0 km/hr
Breaking force is 8,000 N
80 km/hr is the velocity, not the acceleration. Just use Newton's second law and some kinematics and you should solve this problem easily.

What tension must a 50.0 cm length of string support in order to whirl an attached 1,000.0 gram stone in a circular path at 5.00 m/s?


I used the formula F= mv^2/ r

= (1,000.0 g) (5.00 m/s)/ 50.0 cm
= 1,000.0 x 5.00 g*m/s
____________________
50.0

I wanted to know if I was tackling this question correctly..if not what am I doing wrong?
You might want to check the units on that again. I suggest you stick to kg, m, and s.
 
terpsgirl...for the first problem...use the equation that states that impulse = change in momentum...the equation is:
Force * time = change in velocity * mass.

Think of what the original velocity is, and the final velocity...and u should be able to find the change in the velocity. Basically plug in your results...and solve for time.

for the second problem...i would check ur units...notice what unit ur expressing r in...and look at the units ur measuring speed in. Remeber that u should measure everything in kg's, meters and seconds.
 
Last edited:
terpsgirl said:
How much time would be requird to stop a 2,000 kg car that is moving at 80.0 km/hr if the braking force is 8,000 N?

First convert to the correct units.
Car = 2000kg.
Speed = 22.22... m/s.
Braking force = 8000N.

Using F=MA. 8000=2000A, the 8000N force acting against the car will create a deceleration of magnitude 8000/2000, thus, a = -4m/s/s.

U = 22.22..., V = 0, a = -4, t = ?
V = u + at
0 = (200/9) + (-4t)
(200/9) = 4t
t = 5, 5/9 seconds
= 5.56 seconds (2dp)


What tension must a 50.0 cm length of string support in order to whirl an attached 1,000.0 gram stone in a circular path at 5.00 m/s?


I used the formula F= mv^2/ r

= (1,000.0 g) (5.00 m/s)/ 50.0 cm
= 1,000.0 x 5.00 g*m/s
____________________
50.0

I wanted to know if I was tackling this question correctly..if not what am I doing wrong?

THX!

I haven't studied the concept used in question 2, but the equation looks like it would be effective. However, [always] convert to more useful units. You should be working in m/s, kgs, Ns and M.
 

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