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Centripetal force

by dance_sg
Tags: centripetal, force
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dance_sg
#1
Jul27-09, 08:37 PM
P: 113
1. The problem statement, all variables and given/known data
A 1.00 x10^3 kg car is moving through a flat curve on a road at a velocity of 30.0 m/s. If the coefficient of friction between the road and the tires is 0.600, the radius of the curve is


2. Relevant equations
r=v^2/(coefficitent of friction)(g), r=mv^2/F


3. The attempt at a solution
I tried two ways so solve this question, but im not sure which was is correct.
the first thing i did was, find F by multiplying 9.81m/s2 and the mass (1000). then plugging that into the r=v^2/f. Then i used the first formula i provided above and just plugged all the variables in (excluding mass). Does the mass need to somehow be in there?
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diazona
#2
Jul27-09, 09:05 PM
HW Helper
P: 2,155
In [itex]r = mv^2/F[/itex], the force should be the centripetal force that holds the car in the curve, not the weight of the car.
dance_sg
#3
Jul27-09, 09:10 PM
P: 113
so 30^2 divided by 0.600 times 9.81m/s2 giving me 153m, would be the correct answer?

diazona
#4
Jul27-09, 09:13 PM
HW Helper
P: 2,155
Centripetal force

Yep, that's it. But you should make sure you get the same answer both ways.
dance_sg
#5
Jul27-09, 09:16 PM
P: 113
Alrite. thank you =)


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