Register to reply 
Centripetal force 
Share this thread: 
#1
Jul2709, 08:37 PM

P: 113

1. The problem statement, all variables and given/known data
A 1.00 x10^3 kg car is moving through a flat curve on a road at a velocity of 30.0 m/s. If the coefficient of friction between the road and the tires is 0.600, the radius of the curve is 2. Relevant equations r=v^2/(coefficitent of friction)(g), r=mv^2/F 3. The attempt at a solution I tried two ways so solve this question, but im not sure which was is correct. the first thing i did was, find F by multiplying 9.81m/s2 and the mass (1000). then plugging that into the r=v^2/f. Then i used the first formula i provided above and just plugged all the variables in (excluding mass). Does the mass need to somehow be in there? 


#2
Jul2709, 09:05 PM

HW Helper
P: 2,155

In [itex]r = mv^2/F[/itex], the force should be the centripetal force that holds the car in the curve, not the weight of the car.



#3
Jul2709, 09:10 PM

P: 113

so 30^2 divided by 0.600 times 9.81m/s2 giving me 153m, would be the correct answer?



#4
Jul2709, 09:13 PM

HW Helper
P: 2,155

Centripetal force
Yep, that's it. But you should make sure you get the same answer both ways.



#5
Jul2709, 09:16 PM

P: 113

Alrite. thank you =)



Register to reply 
Related Discussions  
Ranking net force/ centripetal force problem  Introductory Physics Homework  1  
Centripetal Force  Introductory Physics Homework  6  
Centripetal force help  Introductory Physics Homework  5  
Centripetal force  Introductory Physics Homework  1 