Learning Matrix Algebra for Chemical Equations

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Discussion Overview

The discussion centers around the application of matrix algebra in forming chemical equations, with participants exploring the relationship between chemical reactions and mathematical representations. The scope includes conceptual understanding and technical explanations related to chemical equations.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant requests clarification on how to use matrix algebra to form a chemical equation.
  • Another participant asserts that chemical equations are derived from experimentation rather than mathematics, seeking more explicit details.
  • A participant shares a chemical equation involving various reactants and products, questioning how specific coefficients (like (x-1), (4-x), and 2x) are determined.
  • A participant expresses confusion regarding the notation used in the equation and requests it to be reformatted for clarity.
  • Another participant mentions the necessity of balancing charge and the number of atoms on each side of the equation, suggesting that algebraic methods could be applied but expresses fatigue in engaging further at that moment.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus; there are competing views on the role of mathematics in forming chemical equations, and the discussion remains unresolved regarding the specific algebraic methods applicable to the example provided.

Contextual Notes

There are limitations in the clarity of the chemical notation presented, and the assumptions underlying the algebraic approach to balancing the equation are not fully explored.

Turtle
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Can someone explain to me how to use matrix algebra, to form a chemical equation?
 
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Chemical equations are formed by experimentation, not mathematics. Can you be more explicit?
 
I have a little article on it ,but it does not explain much.
In the article Ce+4, H20, CH2(CO2H)2 are the reactants and CO2, H+, Ce+3, HCO2H are the products.
The equation is CH2(C02H)2+2H2O+2xCe+4=(x-1)CO2+(4-x)HCO2H+2x-Ce+3+2xH+
How does one obtain the (x-1), (4-x), and the 2x?
 
Last edited:
Originally posted by Turtle
The equation is CH2(C02H)2+2H2O+2xCe+4=(x-1)CO2+(4-x)HCO2H+2x-Ce+3+2xH+

Sorry, but this makes no sense to me. I am assuming that "Ce+4" should be "Ce+4" and not "Ce plus 4".

Can you retype this using superscripts and subscripts?
 
Turtle:

Please retype that using {sup} {/sup} and {sub}{/sub} so the forum can recognise it.

(Replace curlies with square brackets of course)
 
Charge has to balance, number of atoms on each side has to balance, so I'm sure you could get somewhere algebraically, I'm too tired to have a look right now, sorry.
 

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