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Question with large number?electron charge? 
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#1
Jul3109, 10:34 PM

P: 55

1. The problem statement, all variables and given/known data
The electric charge of an electron is 1.6 x 10^19 C. What is the force exerted between two electrons separated by one meter? Is it attractive or repulsive? 2. Relevant equations F= K Q1Q2 / D^2 3. The attempt at a solution Im horrible with large numbers and especially at negative exponents....so this is a guess K = 9x 10^9 N x m^2/c^2 Q1 = 1.6 x 10^19 C Q2 = 1.6 x 10^19 C D= 1 m F= 9 x 10 ^9 N x m^2 X ( 1.6x 10 ^19 C x 1.6x 10 ^19 C / 1^2 m) F= 9 x 10 ^9 N x m X (3.2 x 10^19 C^2 ) F= 28.8 x 10^28 NxmxC^2.....is the answer i got.... I know i am completely off but how can i do this ...this is basically math but im just not with well large numbers... 


#2
Jul3109, 10:43 PM

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P: 4,437

F= 9 x 10 ^9 N x m X (3.2 x 10^19 C^2 )
This step is wrong. 1.6x10^19 X 1.6x10^19 = ? 


#3
Jul3109, 11:06 PM

P: 55

2.56 x 10^38???? 1.6 x 1.6 = 2.56 but what about the 10^19? do i add them or does it stay the same???? Actually now i got 2.6 x 10 ^38...by multiplying both 


#4
Aug109, 03:41 AM

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P: 4,437

Question with large number?electron charge?



#5
Aug109, 09:03 AM

Mentor
P: 12,070

Do you have a calculator that you can doublecheck things like this? If not, Google can be used as a calculator: http://www.google.com/#hl=en&q=1.6e...fp=MyOrnw0Pu0 Note the computerstandard "e19" to signify "×10^{19} " 


#6
Aug109, 10:58 AM

P: 55




#7
Aug109, 11:04 AM

P: 55

Well let me put what i have..... F=9 x 10^9 N x m^2/c^2 X( 2.6 x 10^38 c^2 /1 m^2)
that is what i have...do i cancel out the m^2 and c^2? from both sides? so that only the N is remaining? 


#8
Aug109, 11:07 AM

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#9
Aug109, 11:11 AM

P: 55




#10
Aug109, 11:39 AM

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