Finding the function of a Parabola


by whitehorsey
Tags: function, parabola
whitehorsey
whitehorsey is offline
#1
Aug7-09, 01:43 AM
P: 190
1. The graph of a quadratic function (a parabola) has x-intercepts -1 and 3 and a range consisting of all number less than or equal to 4. Determine an expression for the function.



2. none



3. I do not know how to use the intercepts and the range and manipulate it in to a function. Can you show me step by step? Thank You!
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Дьявол
Дьявол is offline
#2
Aug7-09, 03:26 AM
P: 365
The parabola has formula y=A(x+B)2+C
You got the intercepts i.e y=0, x1=-1, x2=3

Have you ever learned about Vieta's formulas?

x1+x2=-b/a
x1*x2=c/a

where

x2+(b/a)x+c/a=0

You already got the solutions of the quadratic equation.
Mark44
Mark44 is offline
#3
Aug7-09, 01:28 PM
Mentor
P: 21,067
In general, the graph of a parabola is given by the equation y = ax2 + bx + c, which can also be written as y = a(x - r1)(x - r2). Since you are given the two x-intercepts, you should be able to figure out what r1 and r2 are in the second equation I showed.

So all you need to do is determine that value of a.

Since the range is all numbers <= 4, the parabola opens downward. The vertex of a parabola is a point on the parabola that is lower than all others (for a parabola that opens upward) or higher than all others (for one that opens downward). The vertex is always midway between the two x-intercepts, provided that there are two x-intercepts. With this information you should be able to find the coordinates of the vertex, and from them the value of a in the parabola's equation.

whitehorsey
whitehorsey is offline
#4
Aug15-09, 05:06 PM
P: 190

Finding the function of a Parabola


Ok Thank You!


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