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Force necessary to support mass on Hydraulic Jack? 
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#1
Aug1709, 04:38 PM

P: 14

1. The problem statement, all variables and given/known data
Piston 1 in the figure has a diameter of 1.31 cm. distance of 2 in Piston 2 has a diameter of 7.91 cm. distance of 10 in In the absence of friction, determine the force F, necessary to support an object with a mass of 904 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless). 2. Relevant equations F1*d1 = Fp*d2, where d1 is the moment arm of F1, and d2 is the moment arm of Fp. 3. The attempt at a solution Fp = (F1*d1)/d2 (904)(9.81)/(pi)(0.003955)^2= F/(pi)(0.00655)^2 F=242.98 N which was incorrect. anyone have an idea of what I should do and what equation to use? Thanks! 


#2
Aug1709, 07:32 PM

Mentor
P: 12,074

I think we'll need to see the figure before we can help you out.



#3
Aug1709, 09:32 PM

P: 14




#4
Aug1709, 10:20 PM

PF Gold
P: 619

Force necessary to support mass on Hydraulic Jack?
Neglecting the height difference means the pressure should be the same, thus [tex]F_1 A_1 = F_2 A_2 [/tex]
This is would be the force exerted on the small piston. You should know how to find the force needed by the hand from this. 


#5
Aug1709, 11:33 PM

Mentor
P: 12,074

You have the equation to find Fp given F1. 


#6
Aug1809, 01:38 PM

P: 14

ok. I used the equation given and solved for Fp. I had (242.98)(pi*(0.03955)^2))/(pi)*(0.00655)^2=Fp=8858.92 N, which is also incorrect.
what am I doing wrong? 


#7
Aug1809, 03:23 PM

P: 14

nvm. I solved it! thanks everyone for your input!



#8
Mar111, 07:37 PM

P: 8




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