Application of Coloumb's Law to electroscope


by Theelectricchild
Tags: application, coloumb, electroscope
Theelectricchild
Theelectricchild is offline
#1
Jun30-04, 06:38 PM
P: 258
Hi there, I am having a bit of difficulty with this problem dealing with a little more difficult application of Couloumbs Law.

A large electroscope has two wires that are 75-cm long w/22g balls at the ends. When charged, all the charge resides on the balls (Q/2 for each ball) If the wires each make a 30 degree angle with the vertical, what total charge Q must have been applied to the electroscope?

So I set up my free body diagrams and I know how to figure out the weight force and i believe i can get tension--- but what should I be doing to know how much force electrical force is applied (Repulsion in this case since both charges are positive) to make that 30 degree angle to the vertical?

I need to be thinking back to mechanics a little bit =P

Any help would be appreciated--- thank you.
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Gza
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#2
Jul1-04, 04:27 AM
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P: 525
but what should I be doing to know how much force electrical force is applied
Use Coulomb's Law. Also observe the system is in static equilibrium.
Theelectricchild
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#3
Jul2-04, 06:26 PM
P: 258
yes net force is = to 0 because a = 0. Thank you I noticed that actually right after i posted this--- silly me.

rayjohn01
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#4
Jul17-04, 08:23 AM
P: 284

Application of Coloumb's Law to electroscope


Down ward force = mg applied to each side this must be resolved horizontally to equal the charge force which opposes it -- a little trigonometry.
JohnDubYa
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#5
Jul17-04, 12:14 PM
P: 1,322
There is no horizontal component of a downward force.
rayjohn01
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#6
Jul17-04, 12:59 PM
P: 284
John not directly your right , but the leaves are held apart by a horizontal force and they are trying to fall due to a vertical force , obviously something connects these two.
JohnDubYa
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#7
Jul17-04, 02:17 PM
P: 1,322
It isn't the force of gravity, but rather the tension in the leaves, that has the horizontal force component that opposes the charge force.


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