Register to reply

Group cohomology problem

by wofsy
Tags: cohomology
Share this thread:
wofsy
#1
Aug29-09, 09:55 AM
P: 707
A group,G, contains a subgroup,Z, that is isomorphic to the integers.

Z is maximal in the sense that if for any g such that some power g^m is in Z then g is already in Z.

Is it true that any cohomology class ,h, in H^1(G;Z/2) that pulls back to the generator of H^1(Z;Z/2) via the inclusion homomorphism has trivial self-cup products? i.e. is h cup h = 0 in H^2(G;Z/2)?
Phys.Org News Partner Science news on Phys.org
Experts defend operational earthquake forecasting, counter critiques
EU urged to convert TV frequencies to mobile broadband
Sierra Nevada freshwater runoff could drop 26 percent by 2100

Register to reply

Related Discussions
Cohomology = invariant forms Differential Geometry 1
De Rham cohomology Differential Geometry 10