## Why is the non headon collision between an object with momentum and an object at rest

Why does a non head on collision between objects with momentum and an object without momentum result in a 90 degree split? (objects have similar mass)

Could you please represent this in vector form? I'm not sure how I could represent this because it's not a head on collision but a side swipe....
 PhysOrg.com physics news on PhysOrg.com >> Study provides better understanding of water's freezing behavior at nanoscale>> Soft matter offers new ways to study how ordered materials arrange themselves>> Making quantum encryption practical
 Recognitions: Homework Help Normallly the objects have to be the same size, and there can be no losses in the collision (elastic collision), and the objects have to be free to travel in any direction, at least any direction on a plane.
 well yea those conditions are assumed

## Why is the non headon collision between an object with momentum and an object at rest

 I still don't get how the collision results in a 90 degree angle, could someone show me some vector calculation with variables

 Quote by shredder666 I still don't get how the collision results in a 90 degree angle, could someone show me some vector calculation with variables
You have to write down the x and y components of momentum and energy, and solve the equations, See Andy Mason's post #5 in
http://www.physicsforums.com/showthr...ion+equal+mass
and determine what kind of triangle with sides A, B, and C (if any) satisfies the relation A2+B2 = C2.
 oh ok thanks