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Finding time from start to rest

by MellowOne
Tags: rest, start, time
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MellowOne
#1
Sep8-09, 07:59 PM
P: 44
1. The problem statement, all variables and given/known data
A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t) = bt^2 - ct^3, where b = 2.30 m/s^2 and c = 0.120 m/s^3.

How long after starting from rest is the car again at rest?


2. Relevant equations
dx/dt


3. The attempt at a solution
The problem I'm having with this question is I can't figure out how you can find the deceleration after the car stops accelerating. I know at t = 0 the velocity is 0 m/s, at t = 5s the velocity is 14m/s, and at t = 10s, the velocity is 10m/s this means the car decelerated from t = 5s to t = 10s. How do I find the deceleration to find how long it took the car to reach maximum velocity assuming it's 14.0m/s to come back to rest?
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w3390
#2
Sep8-09, 08:12 PM
P: 344
Try using the fact that a=(delta v)/(delta t)
MellowOne
#3
Sep8-09, 08:22 PM
P: 44
Ok, I got it...I just took the derivative of the distance formula which would make it into the velocity formula. Then I set the velocity equal to 0 and used the quadratic equation to find t.

w3390
#4
Sep8-09, 08:34 PM
P: 344
Finding time from start to rest

Sounds right


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