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Pressure energy(fluid mechanics) |
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| Sep19-09, 08:38 AM | #1 |
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Pressure energy(fluid mechanics)
Can any one please help me on the term pressure energy what does it really mean and If possible the calculations involved with it!!
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| Sep19-09, 09:19 AM | #2 |
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Pressure times volume is energy. So if that product changes then the energy has changed.
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| Sep20-09, 02:22 AM | #3 |
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Strictly speaking isn't change in volume times a constant pressure energy ?
so if you had a situation where your volume stayed constant but your volume changed you would have a change in enthalpy ? i.e dU = TdS - PdV dH = TdS + VdP |
| Sep29-09, 06:23 AM | #4 |
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Pressure energy(fluid mechanics)But what is really that volume and the pressure. May you please elaborated it, Probably by using the model for the derivation for Bernouli's Theorem! You know what, I know its reasonable for the pressure energy to be involved i the calculations for bernouli's theorem, But I was shocked when it was written that; Pressure energy=mgh Thank you!! |
| Sep29-09, 06:28 AM | #5 |
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Excuse me! Am really out of phase for what you just explained! May you tell ,e in detail may be would solve my problem! But I was in the derivation for Bernouli's theorem, How can pressure energy=mgh Where h=Height above the point of which total energy is to be calculated! And seriously am not yet familiar with enthalpy so may you elaborate more! Thank you! |
| Sep29-09, 09:15 AM | #6 |
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Similarly, if you are interested in the work done by the heart in one heartbeat you can plot the left ventricular pressure by the left ventricular volume and find the area enclosed over one heartbeat. If you are interested in the amount of work being done on a differential element of a fluid flow you can do the same thing. |
| Oct2-09, 08:46 AM | #7 |
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Its under the derivation of Bernouli's theorem! |
| Nov25-10, 02:09 PM | #8 |
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to move the subject 'pressure energy' a bit back from math to physics the atachement Zeppos10 added to the following link might be usefull:
http://www.physicsforums.com/showthr...errerid=219693 |
| Nov25-10, 07:10 PM | #9 |
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| Nov26-10, 02:12 AM | #10 |
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Recognitions:
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static_pressure_energy + kinetic_energy + gravitational_potential_energy = constant (Note Bernoulli's equation assumes no external work is performed). For the gravitational component, using water as an example, as depth increases, static_pressure_energy increases, gravitational_potential_energy decreases, and vice versa. |
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