Quantum mechanics in atoms question

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SUMMARY

The discussion centers on calculating the wavelength of a photon absorbed by a hydrogen atom during a transition from the 3d level (n=3) to the 4f level (n=4). The relevant formula is wavelength = hc/delta E, where delta E is the absolute value of the energy difference between the two levels, calculated as |E4 - E3|. For hydrogen, the energy levels are defined by E_i = -13.6/n^2 (in eV), confirming that the absolute energy difference is crucial for determining the wavelength of the absorbed photon.

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jazzchan
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The question is:
A hydrogen atom absorbs a photon and makes a transition from a 3d level to a 4f level. What is the wavelength of the absorbed photon ?

As i know 3d is n = 3, 4f is n = 4

and wavelength = hc/delta E

so the deltaE is E4 - E3 or E3 - E4 ??

thanks..
 
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I think that's right. You also need to know what the energy is (compared to ionization energy, for instance) at a given principle quantum number.
 
Just use the absolute value of E4 - E3, because all you are interested in is the AMOUNT of energy needed to make the transition, which is a positive value. So it makes no difference if you use E4 - E3 or E3 - E4, since the absolute value produces the same result.

Since this is hydrogen, then [tex]E_i = -13.6/n^2[/tex] (in eV).
 

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