uniform electric field


by tag16
Tags: electric, field, uniform
tag16
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#1
Sep20-09, 03:03 PM
P: 98
1. The problem statement, all variables and given/known data
A proton moves at 4.50x10^5 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60x10^3 N/C. Ignoring any gravitational effects, find a) the time interval required for the proton to travel 5.00 cm horizontally b) its vertical displacement during the time interval in which it travels 5.00 cm horizontally c) the horizontal and vertical components of its velocity after it has traveled 5.00 cm horizontally.

2. Relevant equations
a= qE/m


3. The attempt at a solution

I know I need to use the above equation at some point in this problem but I have no idea how to go about finding the time interval.
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tiny-tim
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#2
Sep20-09, 05:03 PM
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Hi tag16!

Treat this exactly as you would a projectile under gravity

calculate the acceleration, and do the x and y components separately.
tag16
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#3
Sep20-09, 07:50 PM
P: 98
ok for the formula for acceleration a=qE/m how do you find E? q= 9.60x10^3 right? thanks

tiny-tim
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#4
Sep21-09, 02:36 AM
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uniform electric field


(try using the X2 tag just above the Reply box )
Quote Quote by tag16 View Post
ok for the formula for acceleration a=qE/m how do you find E? q= 9.60x10^3 right? thanks
No, q is charge, and is in coulombs (C)

E is the field, in newtons per coulomb (N/C) E = 9.60x103
tag16
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#5
Sep21-09, 07:47 AM
P: 98
ok...not sure how to figure out q then since it's not given in the problem.
tiny-tim
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#6
Sep21-09, 07:51 AM
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It's the same as the charge on an electron (times minus-one, of course) does that help?
tag16
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#7
Sep21-09, 07:56 AM
P: 98
oh yeah I forgot about that...1.602x10^-19


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