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Uniform electric field 
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#1
Sep2009, 03:03 PM

P: 98

1. The problem statement, all variables and given/known data
A proton moves at 4.50x10^5 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.60x10^3 N/C. Ignoring any gravitational effects, find a) the time interval required for the proton to travel 5.00 cm horizontally b) its vertical displacement during the time interval in which it travels 5.00 cm horizontally c) the horizontal and vertical components of its velocity after it has traveled 5.00 cm horizontally. 2. Relevant equations a= qE/m 3. The attempt at a solution I know I need to use the above equation at some point in this problem but I have no idea how to go about finding the time interval. 


#2
Sep2009, 05:03 PM

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P: 26,151

Hi tag16!
Treat this exactly as you would a projectile under gravity … calculate the acceleration, and do the x and y components separately. 


#3
Sep2009, 07:50 PM

P: 98

ok for the formula for acceleration a=qE/m how do you find E? q= 9.60x10^3 right? thanks



#4
Sep2109, 02:36 AM

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P: 26,151

Uniform electric field
(try using the X^{2} tag just above the Reply box )
E is the field, in newtons per coulomb (N/C) … E = 9.60x10^{3} 


#5
Sep2109, 07:47 AM

P: 98

ok...not sure how to figure out q then since it's not given in the problem.



#6
Sep2109, 07:51 AM

Sci Advisor
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P: 26,151

It's the same as the charge on an electron (times minusone, of course) … does that help?



#7
Sep2109, 07:56 AM

P: 98

oh yeah I forgot about that...1.602x10^19



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