Totally lost on magnetic flux question

[supermenscher]

A uniform magnetic field of 0.0300T points vertically upward. Find the magnitude of the magnetic flux through each of the 5 sides of the open topped rectangular box, given the dimensions of the box are, length = 0.335m width = 0.12m, and Height = .10m. Find Wb through long side, short side, and bottom.

I have no idea where to start for this question any type of help would be appreciated. Thank you.

 

[gnome]

Depends on how the box is positioned in relation to the magnetic field.

For example, what is the amount of magnetic flux through a surface that is parallel to the magnetic lines of force?

 

[M98Ranger]

Hi there,

I understand that this question may seem daunting, but let's break it down step by step to make it more manageable.

First, let's define what magnetic flux is. Magnetic flux is the measure of the total number of magnetic field lines passing through a given area. In this case, we have a uniform magnetic field of 0.0300T (tesla) pointing vertically upward, and we need to find the magnetic flux through each of the five sides of the open-topped rectangular box.

To find the magnetic flux through each side, we need to use the formula:

Φ = B x A x cosθ

Where Φ is the magnetic flux, B is the magnetic field, A is the area, and θ is the angle between the magnetic field and the surface normal of the area.

Let's start with the long side of the box. The length of the box is given to be 0.335m, and the width is 0.12m. Since the magnetic field is pointing vertically upward, the angle between the magnetic field and the surface normal of the long side is 90 degrees. Therefore, the formula becomes:

Φ = (0.0300T) x (0.335m x 0.12m) x cos90° = 0.01278 Wb (tesla-meter squared)

Similarly, for the short side, the length is 0.12m and the width is 0.10m. Again, the angle between the magnetic field and the surface normal of the short side is 90 degrees, so the formula becomes:

Φ = (0.0300T) x (0.12m x 0.10m) x cos90° = 0.0036 Wb

And for the bottom of the box, the length is 0.335m and the width is 0.12m. However, the angle between the magnetic field and the surface normal of the bottom is now 0 degrees, as the magnetic field is parallel to the surface. So the formula becomes:

Φ = (0.0300T) x (0.335m x 0.12m) x cos0° = 0 Wb

Therefore, the magnetic flux through the long side is 0.01278 Wb, through the short side is 0.0036 Wb, and through the bottom is 0 W