Flex Your Mathletic Muscles Impress the Ladies

  • Context: Undergrad 
  • Thread starter Thread starter eNtRopY
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Discussion Overview

The discussion revolves around solving a specific differential equation of the form y' = k * y^(1/2). Participants explore methods for solving this equation, sharing their approaches and reasoning.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about solving the differential equation and seeks help from others.
  • Another participant suggests that the equation is separable and provides a transformation to facilitate solving it.
  • A different participant proposes a solution for y, but later acknowledges a mistake regarding the inclusion of a constant before squaring.
  • There is a light-hearted exchange regarding the motivations for seeking help, with references to being busy versus being lazy.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the final form of the solution due to the correction regarding the constant. The discussion reflects differing views on the approach to solving the equation.

Contextual Notes

The discussion includes an unresolved mathematical step concerning the inclusion of a constant in the solution, which may affect the final result.

eNtRopY
A few days ago in the physics board, we encountered the following differential equation of the form:

y' = k * y^(1/2).

It's been a long time since I've taken a class in the techniques of solving differential equation, and I can't remember off-hand how to solve this problem. Rather than research the method for solving this problem myself, I thought I'd give you dudes a chance to impress all the beautiful ladies on these boards (e.g. Entropia, Kerrie, Galatea, Kat, Monique, Saint, etc.).

eNtRopY

P.S. If you are a lady, and I have forgotten you, I'm sorry... I don't have a very good memory for names.
 
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In other words, you're lazy and you want us to do your work for you. :smile:

This equation is seperable:

dy/dx = k * y^(1/2)

y^(-1/2) * dy = k * dx
 
Lazy... or too busy?
Anyway,

y = (k*x/2 + C)^2

Thanks... I don't know why I didn't see that right away. I guess I should be embarrassed.

eNtRopY
 
Last edited by a moderator:
Originally posted by eNtRopY
Lazy... or too busy?
Anyway,

y = (k*x/2)^2

Thanks... I don't know why I didn't see that right away. I guess I should be embarrassed.

eNtRopY

You forgot to add a constant before squaring.
 

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