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Pressure on sides and ends of pool, given the pools dimensions and depth |
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| Nov1-09, 09:35 PM | #1 |
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Pressure on sides and ends of pool, given the pools dimensions and depth
1. The problem statement, all variables and given/known data
A swimming pool has dimensions 34.0 m 9.0 m and a flat bottom. When the pool is filled to a depth of 2.30 m with fresh water, what is the force caused by the water on the bottom? I have the answer to this which is 6.90 x 10^6, however I cannot figure out the pressure on the sides or ends. 2. Relevant equations Pressure on bottom = water density X gravity x area 3. The attempt at a solution I understand the water depth has to play into this somehow but I cannot figure out how... I attempted 9.80 x 2 x 9 = 176.4 kN and 9.80 x 2 x 34 = 666.4 kN These were incorrect |
| Nov1-09, 09:56 PM | #2 |
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Recognitions:
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Your relevant equation is wrong.
Check it. |
| Nov1-09, 10:16 PM | #3 |
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Apologies,
ρ = density - P = pressure - F = force - b = bottom of pool - z = area of pool Pb = ρgz Fb = PbA |
| Nov1-09, 10:40 PM | #4 |
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Recognitions:
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Pressure on sides and ends of pool, given the pools dimensions and depth
z is the depth of the water. Now find the pressure at the bottom Pb and then Fb
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