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I don't understand this circuit.. |
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| Nov2-09, 09:58 AM | #1 |
| Nov2-09, 10:28 AM | #2 |
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The text states "You should have no difficulty in figuring out how this circuit works". Which leads me to think you may not have learned from the previous projects or skipped them completely. Remember, when a transistor is in the "on" state it will conduct current and so the voltage across the emitter collector will be low.
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| Nov2-09, 10:40 AM | #3 |
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| Nov2-09, 10:48 AM | #4 |
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I don't understand this circuit..
The transistor stages are set up in such a way that they act as NOT gates. If voltage in the base of one transistor is low then the voltage on the collector side will go up, and if base is high, then the collector voltage will go down. There are two such stages in the schematic, so you have a NOT and a NOT that cancel each other.
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| Nov2-09, 10:50 AM | #5 |
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But what is the voltage across the emitter collector (of Q2) when it is "on", and what voltage is needed to turn the led on?
http://www.ledsmagazine.com/features/4/8/1/MarlFig1 Maybe a simpler way for you to think of this is that when Q2 is "on" it shorts out the led (current flows through R3 and Q2). When Q2 is "off" it is like an open circuit (current flows through R3 and the led). |
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