|Nov2-09, 08:56 PM||#1|
HP strange RPN operation???
I just find an odd behavior on my hp rpn operation. Can someone try the following sequence of entry and explain to me this strange behavior?
Press 5 (any number will do).
Press 'Enter' (this should duplicate 5 to x an y stacks)
Press 'Enter' again (duplicate 5 again so now x,y and z stack are all 5)
Press 'RDn' to rotate stack 4 times (this should bring the stack configuration back to the same, x,y and z stack are all 5. The stack should read (5,5,5,0) for (x,y,z,t).
Now press 10 and then *.
Normally, I would expect the stack to be (50, 5, 5, 0) for (X, Y, Z, T). But if you follow the above step, you will get (50, 5, 5 ,5). Am I missing something here?
|Nov8-09, 03:26 AM||#2|
That is the correct behavior. The T register is not zeroed, but remains the same. If you press 2 / enter / enter / enter, then press + many times, you will get 2, 4, 6, 8, 10, 12, 14, 16...
|Similar Threads for: HP strange RPN operation???|
|BJT(npn) physical operation help!||Atomic, Solid State, Comp. Physics||5|
|closed operation||General Math||3|
|Cutting Operation||Materials & Chemical Engineering||0|
|Binary operation||Set Theory, Logic, Probability, Statistics||3|
|Binary Operation||Calculus & Beyond Homework||3|