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lat lon to ECEF conversion derivation...

 
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Nov29-09, 12:51 AM   #1
 

lat lon to ECEF conversion derivation...


Most texts on geodesy seem to jump right into the formulas for converting LLA to ECEF as follows:

X = [N + H] cos ¢. cos £

Y = [N + H] cos ¢. sin £

Z = [(b 2 /a 2) N + h] sin ¢

My question is, how does one arrive at this? I can't seem to find any derivations for this. Any pointers to some material?
 
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