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lat lon to ECEF conversion derivation... |
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| Nov29-09, 12:51 AM | #1 |
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lat lon to ECEF conversion derivation...
Most texts on geodesy seem to jump right into the formulas for converting LLA to ECEF as follows:
X = [N + H] cos ¢. cos £ Y = [N + H] cos ¢. sin £ Z = [(b 2 /a 2) N + h] sin ¢ My question is, how does one arrive at this? I can't seem to find any derivations for this. Any pointers to some material? |
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| derivation, ecef, lat, lon |
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