Falling object and distance between time intervalsby Jakedidit Tags: 324 meters, bowling ball, d=4.9t^2, falling object, interval distance 

#1
Dec309, 08:04 AM

P: 1

1. The problem statement, all variables and given/known data
Gravity on a falling object causes the object to descend a distance of d=4.9t^2, where d is the distance in meters and t is the time in seconds. A bowling bll is dropped from the top of the Eiffel Tower in Paris, France, which is 324 meters in height. If you neglect any type of air resistance, what is the distance (in meters) that the ball falls during the interval between the 8th and 9th second? 2. Relevant equations d=4.9t^2 is given; Gravity acceleration is 9.8 m/s^2 3. The attempt at a solution Should we calculate the distance the bowling ball will fall in 8 seconds? then 9 seconds? then subtract the two? (Can't fall more than 324 meters) 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 



#2
Dec309, 08:08 AM

P: 5

Calculate how far it has fallen in 8 seconds. Then calculate how far it has fallen in 9 seconds.
If for example in 8 seconds it has fallen 200m and in 9 it has fallen 250m then the distance is 50m. But if your distance at 9 seconds is over 324m then it will have hit the ball between the 8th and 9th second, so you will just take away the distance at the 8th second from 324. 


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