|Dec5-09, 08:43 PM||#1|
A jet engine develops 1 * 10^5 n of thrust in moving the airplane forward at a speed of 900 km/h. What is the power developed by the engine?
I thought I needed to convert 900 km/h to m/s, so I did and I got 15000 m/s.
The only equation I see to use for this is:
P = Fvcosθ
When I used the equation, I got:
P = Fv
= (1*105)(15000 m/s)
= 1.5 * 109
I know I went wrong somewhere because it is multiple choice and that wasn't any of the answers. Please help me see my error(s) and help me get it right. I need this done a.s.a.p. by tomorrow. Thanks.
|Dec5-09, 08:52 PM||#3|
900km/hr= 900000m/s divide by 3600 sec/hr and you get what?
Edit: sorry rootx, missed your response.
|Dec5-09, 08:56 PM||#4|
My mistake. I completely missed that.
900000 m/h /3600 s = 250 m/s
And then I multiply that by the thing I had before:
P = Fv
= (1 * 105 N)(250 m/s)
= 250000 W
= 25 MW
Thanks guys. I got too much going on in my mind right now.
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