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Power developed |
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| Dec5-09, 08:43 PM | #1 |
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Power developed
A jet engine develops 1 * 10^5 n of thrust in moving the airplane forward at a speed of 900 km/h. What is the power developed by the engine?
I thought I needed to convert 900 km/h to m/s, so I did and I got 15000 m/s. The only equation I see to use for this is: P = Fvcosθ When I used the equation, I got: P = Fv = (1*105)(15000 m/s) = 1.5 * 109 I know I went wrong somewhere because it is multiple choice and that wasn't any of the answers. Please help me see my error(s) and help me get it right. I need this done a.s.a.p. by tomorrow. Thanks. |
| Dec5-09, 08:52 PM | #3 |
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900km/hr= 900000m/s divide by 3600 sec/hr and you get what?
Edit: sorry rootx, missed your response. |
| Dec5-09, 08:56 PM | #4 |
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Power developed
My mistake. I completely missed that.
900000 m/h /3600 s = 250 m/s And then I multiply that by the thing I had before: P = Fv = (1 * 105 N)(250 m/s) = 250000 W = 25 MW Thanks guys. I got too much going on in my mind right now.
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