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Complex Fourier Series & Full Fourier Series |
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| Dec9-09, 12:40 AM | #1 |
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Complex Fourier Series & Full Fourier Series
1. The problem statement, all variables and given/known data
Claim: If f(x) is a REAL-valued function on x E [-L,L], then the full Fourier series is exactly equivalent to the complex Fourier series. This is a claim stated in my textbook, but without any proof. I also searched some other textbooks, but still I have no luck of finding the proof. I've already spent an hour thinking about how to show that this is true, but still I am not having much progress. Here is what I've got so far: Full Fourier series is: ![]() where ![]() Complex Fourier series is: ![]() where ![]() And now I am having trouble with this...how can I use the last part to show that if f(x) is REAL-valued, the complex Fourier series can be reduced to the full Fourier series. Can someone please show me how to continue from here? I also don't see how a sum from negative infinity to infinity (for complex Fourier series) can possibly be reduced to a sum from 0 to infinity (for full Fourier series). It seems like I have no hope... 2. Relevant equations As shown above 3. The attempt at a solution As shown above I am really frustrated now and any help is very much appreciated! :) |
| Dec9-09, 04:55 AM | #2 |
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An obvious first step is to use the fact that [itex]e^{in\pi x/L}= cos(n\pi x/L)+ i sin(n\pi x/L)[/itex]. Multiply it out and use the fact that cos(-x)= cos(x), sin(-x)= sin(x).
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| Dec9-09, 05:48 AM | #3 |
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(for simplicity I am taking the interval to be from -pi to pi) Is this a correct proof?? Thanks! |
| Dec9-09, 07:10 PM | #4 |
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Complex Fourier Series & Full Fourier Series
The claim is
"If f(x) is a REAL-valued function on x E [-L,L], then the full Fourier series is exactly equivalent to the complex Fourier series." But nowhere in the proof have I assumed f(x) is real-valued. Is it absolutely necessary for f(x) to be REAL-valued in order to prove that the full Fourier series is exactly equivalent to the complex Fourier series?? |
| Dec10-09, 04:35 AM | #5 |
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That's because the equality of those sums does not depend upon real or complex numbers. We require that F be real valued in order to have the coefficients real numbers.
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| Dec10-09, 07:23 PM | #6 |
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