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another limit using l'hopitals |
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| Jan17-10, 12:54 PM | #1 |
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another limit using l'hopitals
1. The problem statement, all variables and given/known data
limit as x goes to infinity of (1/x^2) - (cscx)^2 2. Relevant equations 3. The attempt at a solution I made it so the denominator is x^2, but then it would 1-inf/inf which isn't indeterminate. i need help setting it up so it would be in indeterminate form. thanks. |
| Jan17-10, 02:30 PM | #2 |
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You probably mean lim x->0, right? Just make a common denominator and combine those two terms into a single fraction. It's probably easier to write 1/sin(x)^2 instead of csc(x)^2, but it will still take several derivatives before you get a nonindeterminant answer from l'Hopital.
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| Jan17-10, 03:28 PM | #3 |
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nope, the question states lim x-> inf
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| Jan17-10, 03:31 PM | #4 |
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another limit using l'hopitals |
| Jan17-10, 03:33 PM | #5 |
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that's what my original problem was
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| Jan17-10, 03:39 PM | #6 |
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| Jan17-10, 03:56 PM | #7 |
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AB |
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