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another limit using l'hopitals

 
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Jan17-10, 12:54 PM   #1
 

another limit using l'hopitals


1. The problem statement, all variables and given/known data
limit as x goes to infinity of (1/x^2) - (cscx)^2


2. Relevant equations



3. The attempt at a solution
I made it so the denominator is x^2, but then it would 1-inf/inf which isn't indeterminate. i need help setting it up so it would be in indeterminate form. thanks.
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Jan17-10, 02:30 PM   #2

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You probably mean lim x->0, right? Just make a common denominator and combine those two terms into a single fraction. It's probably easier to write 1/sin(x)^2 instead of csc(x)^2, but it will still take several derivatives before you get a nonindeterminant answer from l'Hopital.
Jan17-10, 03:28 PM   #3
 
nope, the question states lim x-> inf
Jan17-10, 03:31 PM   #4

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another limit using l'hopitals


Quote by magnifik View Post
nope, the question states lim x-> inf
Then tell me about the limiting behavior of 1/x^2 and csc(x)^2 as x->inf. Is that expression really indeterminant?
Jan17-10, 03:33 PM   #5
 
that's what my original problem was
Jan17-10, 03:39 PM   #6

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Quote by magnifik View Post
that's what my original problem was
Sketch a graph of each one. The limiting behavior should be visually obvious.
Jan17-10, 03:56 PM   #7
 
Quote by magnifik View Post
1. The problem statement, all variables and given/known data
limit as x goes to infinity of (1/x^2) - (cscx)^2


2. Relevant equations



3. The attempt at a solution
I made it so the denominator is x^2, but then it would 1-inf/inf which isn't indeterminate. i need help setting it up so it would be in indeterminate form. thanks.
The limit does not exist by any means. If needed, a proof can be given.

AB
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