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Another limit using l'hopitals 
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#1
Jan1710, 12:54 PM

P: 361

1. The problem statement, all variables and given/known data
limit as x goes to infinity of (1/x^2)  (cscx)^2 2. Relevant equations 3. The attempt at a solution I made it so the denominator is x^2, but then it would 1inf/inf which isn't indeterminate. i need help setting it up so it would be in indeterminate form. thanks. 


#2
Jan1710, 02:30 PM

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You probably mean lim x>0, right? Just make a common denominator and combine those two terms into a single fraction. It's probably easier to write 1/sin(x)^2 instead of csc(x)^2, but it will still take several derivatives before you get a nonindeterminant answer from l'Hopital.



#3
Jan1710, 03:28 PM

P: 361

nope, the question states lim x> inf



#4
Jan1710, 03:31 PM

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Another limit using l'hopitals



#5
Jan1710, 03:33 PM

P: 361

that's what my original problem was



#6
Jan1710, 03:39 PM

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#7
Jan1710, 03:56 PM

P: 665

AB 


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