# another limit using l'hopitals

by magnifik
Tags: lhopitals, limit
 P: 361 1. The problem statement, all variables and given/known data limit as x goes to infinity of (1/x^2) - (cscx)^2 2. Relevant equations 3. The attempt at a solution I made it so the denominator is x^2, but then it would 1-inf/inf which isn't indeterminate. i need help setting it up so it would be in indeterminate form. thanks.
 HW Helper Sci Advisor Thanks P: 24,423 You probably mean lim x->0, right? Just make a common denominator and combine those two terms into a single fraction. It's probably easier to write 1/sin(x)^2 instead of csc(x)^2, but it will still take several derivatives before you get a nonindeterminant answer from l'Hopital.
 P: 361 nope, the question states lim x-> inf
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Thanks
P: 24,423

## another limit using l'hopitals

 Quote by magnifik nope, the question states lim x-> inf
Then tell me about the limiting behavior of 1/x^2 and csc(x)^2 as x->inf. Is that expression really indeterminant?
 P: 361 that's what my original problem was
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