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From the nature of light unit |
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| Jan22-10, 12:20 PM | #1 |
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From the nature of light unit
1. The problem statement, all variables and given/known data
Q: An electromagnetic radiation has a frequency of 5.00 x 10^14 Hz. a) Calculate its wavelength in a vacuum, in meters and nanometers. b) Calculate its wavelength in water. c) Is this radiation visible? If so, what is its colour? d) What is the index of refraction of a medium in which the speed of this radiation is 2.54 x 10^8 m/s? e) Where would you encounter this radiation in your daily life? I just need help with e) 2. Relevant equations 3. The attempt at a solution 10. An electromagnetic radiation has a frequency of 5.00 x 1014 Hz. a) Calculate its wavelength in a vacuum, in meters and nanometers. Given: The speed of light in a vacuum is 3.00 x 108 m/s. Required: the wavelength of electromagnetic radiation, that has a frequency of 5.00 x 1014 Hz, in a vacuum, in meters and nanometers. Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med}) Therefore wavelength(vac) = (n)(wavelength{med}) and wavelength(med) = wavelength(vac)/n Solution: λ = (3.00 x 108 m/s) / (5.00 x 1014 Hz) Λ = 6.00 x 10-7 m or 600nm b) Calculate its wavelength in water. Given: wavelength = 0.6 x 10^-6m or 600nm n = 1.33 for water Required: wavelength(med) Analysis: c=(f)(wavelength{vac}) and c=(n)(wavelength{med}) therefore wavelength(vac) = (n)(wavelength{med}) and wavelength(med) = wavelength(vac)/n Solution: wavelength(med) = (0.6 x 10^-6m)/1.33 = 4.51 x 10^-7 or 451 nm Phrase: The wavelength in water of an electromagnetic radiation, that has a frequency of 5.00 x 1014 Hz, is 451 nm c) Is the radiation visible? If so, what is its colour? Yes, the radiation is visible as orange (in a vacuum), since orange has a range of 590nm to 610nm on the spectrum and violet (in water), since violet has a range of 400nm – 450nm. d) What is the index of refraction of a medium in which the speed of this radiation is 2.54 x 108 m/s? Given: Speed of light: 3.00 x 108 m/s Speed of radiation in the medium: 2.54 x 108 m/s Required: the index of refraction. Analysys: n = speed of light in a vacuum/speed of light in a medium Solution: n = (3.00 x 108 m/s)/(2.54 x 108 m/s) n = 1.18 e) Where would you encounter this radiation in your daily life? The only searches that come back to me are bronze....HELP! |
| Jan22-10, 12:52 PM | #2 |
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Recognitions:
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| Jan22-10, 01:01 PM | #3 |
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I think it's between tv/fm radios and microwaves/radar? Am I wrong?
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| Jan22-10, 01:05 PM | #4 |
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From the nature of light unit
was i wrong when i said bronze?
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| Jan22-10, 01:51 PM | #5 |
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![]() Where does it lie now? |
| Jan22-10, 02:00 PM | #6 |
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In the visible light spectrum
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| Jan22-10, 02:12 PM | #7 |
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| Jan22-10, 02:16 PM | #8 |
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Hydrogen gas, neon gas, sodium or mercury vapour?
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| Jan22-10, 03:16 PM | #9 |
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Recognitions:
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