
#1
Feb210, 11:50 PM

P: 1

1. The problem statement, all variables and given/known data
An object is thrown vertically upward such that it has a speed of 47 m/s when it reaches two thirds of its maximum height above launch point. Find maximum height h. 2. Relevant equations V^2Vo^2 = 2gh or V^2Vo^2 = 2g(1/3H)? 3. The attempt at a solution Final velocity= 0 m/s Velocity at 2/3h= 47 m/s Acceleration of gravity=9.8 m/s^2 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution 



#2
Feb310, 01:17 AM

P: 286

dont confuse yourself .. You can solve the following equations to get the max. Height :
(47)^2  vo^2 = 2g(2/3) ymax 0  vo^2 = 2g ymax You can as a start subtract the second equation from the first .. And keep in mind that you are using g as a vector not a scalar value in that equation .. 


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