Finding max. height of object thrown vertically upard

by chuntaro
Tags: gravity, height, maximum, velocity
chuntaro is offline
Feb2-10, 11:50 PM
P: 1
1. The problem statement, all variables and given/known data
An object is thrown vertically upward such that it has a speed of 47 m/s when it reaches two thirds of its maximum height above launch point. Find maximum height h.

2. Relevant equations

V^2-Vo^2 = 2gh
V^2-Vo^2 = 2g(1/3H)?

3. The attempt at a solution
Final velocity= 0 m/s
Velocity at 2/3h= 47 m/s
Acceleration of gravity=9.8 m/s^2
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
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thebigstar25 is offline
Feb3-10, 01:17 AM
P: 286
dont confuse yourself .. You can solve the following equations to get the max. Height :

(47)^2 - vo^2 = 2g(2/3) ymax
0 - vo^2 = 2g ymax

You can as a start subtract the second equation from the first .. And keep in mind that you are using g as a vector not a scalar value in that equation ..

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