# Finding max. height of object thrown vertically upard

by chuntaro
Tags: gravity, height, maximum, velocity
 P: 1 1. The problem statement, all variables and given/known data An object is thrown vertically upward such that it has a speed of 47 m/s when it reaches two thirds of its maximum height above launch point. Find maximum height h. 2. Relevant equations V^2-Vo^2 = 2gh or V^2-Vo^2 = 2g(1/3H)? 3. The attempt at a solution Final velocity= 0 m/s Velocity at 2/3h= 47 m/s Acceleration of gravity=9.8 m/s^2 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution
 P: 286 dont confuse yourself .. You can solve the following equations to get the max. Height : (47)^2 - vo^2 = 2g(2/3) ymax 0 - vo^2 = 2g ymax You can as a start subtract the second equation from the first .. And keep in mind that you are using g as a vector not a scalar value in that equation ..

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