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graphical method to find magnitude and direction |
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| Jun17-12, 10:47 AM | #18 |
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graphical method to find magnitude and direction
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| Jun17-12, 10:51 AM | #19 |
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what graph is correct?
is this problem use pythagorean theorem or component method? |
| Jun17-12, 11:04 AM | #20 |
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you can always use either the cosine formula or the component method
(pythagoras only works for right-angled triangles … for general triangles you need the cosine formula) |
| Jun17-12, 11:07 AM | #21 |
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actually this is in my book .. FB-FA due to west
and first i used component method which is x=90 y=0 x= 35 y=130 sum= x=125 y= 130 then i used pythgorean theorem |
| Jun17-12, 11:14 AM | #22 |
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. cosine formula?.. our professor did not teach about that..
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| Jun17-12, 11:16 AM | #23 |
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ah, i see what you mean … yes, when you have the x and y components, you can then use the pythgorean theorem to give you the magnitude ![]() (your answer should be "a magnitude of … newtons at an angle of … north of west") |
| Jun17-12, 11:45 AM | #24 |
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yes, when you have the x and y components, you can then use the pythgorean theorem to give you the magnitude
![]() (your answer should be "a magnitude of … newtons at an angle of … north of west")[/QUOTE] -is only one answer for this problem?.. |
| Jun17-12, 11:46 AM | #25 |
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but the result is not 142 ang 67 degree.
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| Jun17-12, 11:52 AM | #26 |
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can you give me a specific formula?
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| Jun17-12, 11:54 AM | #27 |
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that's 67° north of east, the question asks for the angle with respect to west
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| Jun17-12, 11:57 AM | #28 |
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| Jun17-12, 12:36 PM | #29 |
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so if i subtract the angle will be in north of west
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| Jul1-12, 09:00 AM | #30 |
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Hi guys.....
I am new to his website and i dunno if i am using the correct place to ask my question ![]() Well the question is: When a vector is given say A: a i^+b j^+ck^ then how to find the angle between the vector and x-axis: y- axis; z-axis Thanq for ur time ......
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| Jul1-12, 10:44 AM | #31 |
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![]() For starters, to find angle from x axis, think about taking an unit vector along x-axis, and use the concept of dot-product. |
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