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Angular acceleration 
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#1
Feb510, 04:28 PM

P: 3

1. The problem statement, all variables and given/known data
A highspeed drill rotating ccw at 2200rpm comes to a halt in 2.80 s. What is the drill's angular acceleration? 2. Relevant equations (where w = angular velocity) w = 2╥/T v = wr a = v^2/r a = w^2*r 3. The attempt at a solution I start by calculating w. So first I took it to rev per second and then second per revolution which came to be 0.027 seconds per revolution. So w = 2╥/0.027 = 232.71 radians. Now I'm stuck because I don't have r (radius). I've tried going backwards to get r from v, but to no success since v depends in r as r depends in v. Every equation relating to acceleration seems to need r but I don't see how I can get it. Any ideas would be appreciated. Thanks. 


#2
Feb510, 05:01 PM

HW Helper
P: 6,202

you don't need radius or linear velocity.
[tex]\alpha = \frac{\omega_f  \omega_i}{t}[/tex] 


#3
Feb510, 07:10 PM

P: 3

Thank you. I realized after you posted that equation that it was a nonuniform circular motion problem, I was going about it the wrong way.



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