Register to reply 
Crate on a slope  Angles and Tension 
Share this thread: 
#1
Feb1410, 11:18 AM

P: 365

1. The problem statement, all variables and given/known data
A large empty crate, with its lid in place, has a 9.50 kg mass hanging from a string attached to the center of the lid. If the crate were sitting (at rest) on a flat surface, the string would simply hang straight down such that the mass would not be touching the floor of the crate. The crate is now pushed up a frictionless 10.0 degree slope with an acceleration of 2.25 m/s^2. During the push, what angle does the string make with the lid of the crate? Hint: you will need to solve two equations in two unknowns. 2. Relevant equations f=ma newton's 2nd law 3. The attempt at a solution I found the force required to push it up the ramp f= 9.8(9.5)sin10 = 16.2N Not sure if i even need that but i did it anyways. so i really have no idea what 2 equations i need to get in order to solve the angle of the string? can anyone help me on this please. thank you 


#2
Feb1410, 01:19 PM

P: 432

What about a free body diagram with the pseudo forces included?



#3
Feb1410, 01:56 PM

Sci Advisor
HW Helper
Thanks
P: 26,160

Hi mybrohshi5!
The acceleration of the mass will be the same as that of the crate (and in the same direction). And there are two forces on the mass. So use good ol' Newton's second law on the mass … what do you get? 


#4
Feb1410, 02:16 PM

P: 365

Crate on a slope  Angles and Tension
well the two forces would be the force due to gravity (its weight) and the normal force is that correct?
im a little confused about what i need to find from what you just stated above. thank you for any further explanations 


#5
Feb1410, 02:22 PM

Sci Advisor
HW Helper
Thanks
P: 26,160

Hi mybrohshi5!
Add the two forces (one is unknown, so just give it a letter), and use F = ma. 


#6
Feb1410, 02:27 PM

P: 365

i thought there was a normal force but i guess cause it frictionless there is not a normal force?
im sorry im so lost right now about adding the two forces (one is unknown) and use f = ma 


#7
Feb1410, 02:34 PM

Sci Advisor
HW Helper
Thanks
P: 26,160

I'm asking about the mass hanging, inside it. What is the F_{total} = ma equation for the mass? 


#8
Feb1410, 02:43 PM

P: 365

sorry i was reading the question completely wrong
for some reason i am having a really hard time wrapping my head around what is going on still though and how to find these equations :( the mass will have two forces on it correct. one force will be the weight and the other force will be the force parallel to the ramp just in the opposite direction? im just really confused.... do i need to include tension in these two equations that i am trying to find? 


#9
Feb1410, 02:48 PM

Sci Advisor
HW Helper
Thanks
P: 26,160

Yes, the tension is the only other force on the mass. ok, so solve the vector equation: mg + T = ma. (and get some sleep! ) 


#10
Feb1410, 02:52 PM

P: 365

im trying to figure out how this helps me solve the angle i need to find though....?



#11
Feb1410, 02:54 PM

P: 365

are these the two equations i need:
mgsin(10) + T = ma T  mgsin(theta) = ma 


#13
Feb1410, 04:23 PM

P: 365

goodness i am not exactly sure. i am so confused on how to get two equations for this.
ok, so solve the vector equation: mg + T = ma. when you said this should i solve it for the tension? 


#14
Feb1410, 04:30 PM

Sci Advisor
HW Helper
Thanks
P: 26,160

You will need to take components in a suitable direction, of both a and the forces. You have a choice of three pairs of components: horizontal/vertical slope/normal string/perpendiculartostring … which do you think will be quickest? 


#15
Feb1410, 04:39 PM

P: 365

my guess would be string/perpendicular to the string?
but maybe would it be slope/normal because the angle i am trying to find has to deal with the slope and the crate.... 


#16
Feb1410, 04:54 PM

Sci Advisor
HW Helper
Thanks
P: 26,160




#17
Feb1410, 05:06 PM

P: 365

so in the equation mg + T = ma
do i replace T with the components perpendicular to the string? gosh i feel so stupid right now. i cannot even begin to explain how confused i am about this whole problem :( am i just making it much more difficult than it actually is because thats what i feel i am doing :( 


Register to reply 
Related Discussions  
Tension with Different Angles  Introductory Physics Homework  10  
Angles of tension  Introductory Physics Homework  5  
Projection motion on a slope; f angles that will provide the greastest range  Introductory Physics Homework  6  
Pushing Crate up Frictionless Slope.. Find Work  Introductory Physics Homework  2  
Pulley Problem, 1 crate hanging, 1 crate on an incline  Introductory Physics Homework  1 