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Linearity |
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| Mar19-10, 11:47 PM | #1 |
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Linearity
I'm trying to see if [tex]\rho[/tex]utt + EIuxxxx = 0 is linear or non-linear where [tex]\rho[/tex], E and I are constants.
I got L(u+v) = [tex]\rho[/tex][tex]\delta[/tex]2u2/[tex]\delta[/tex]t2 + EI[tex]\delta[/tex]4u2/[tex]\delta[/tex]x4 + [tex]\rho[/tex][tex]\delta[/tex]2uv/[tex]\delta[/tex]t2 + EI[tex]\delta[/tex]4uv/[tex]\delta[/tex]x4 = Lu + Lv. Does this mean it's linear or is there more to do. |
| Mar20-10, 03:29 AM | #2 |
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That is enough.
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| Mar20-10, 07:14 PM | #3 |
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Cheers.
What about this one then. ut - [tex]\alpha^2[/tex][tex]\nabla^2[/tex]u = ru(M -u) where [tex]\alpha[/tex], r & M are constants. ut - [tex]\alpha^2[/tex][tex]\nabla^2[/tex]u - ru(M -u) = 0 L(u+v+w) = ut(u+v+w) + [tex]\alpha^2[/tex][tex]\nabla^2[/tex]u(u+v+w) - ru(M-u)(u+v+w) = utt + [tex]\alpha^2[/tex][tex]\nabla^2[/tex]u2 - ru2(M-u) + utv + [tex]\alpha^2[/tex][tex]\nabla^2[/tex]uv - ruv(M-u) + utw + [tex]\alpha^2[/tex][tex]\nabla^2[/tex]uw - ruw(M-u) = Lu + Lv + Lw |
| Mar20-10, 11:22 PM | #4 |
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Linearity
Are these equation linear or non-linear?
ut + (1-u)ux = 0 uxx + exutt = sin(x) uxx + uxy + uyy + ux = t2 |
| Mar22-10, 03:47 PM | #5 |
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Someone help please.
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