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Time it takes to lift boxes when man has an average useful power output of 41.4 W 
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#1
Mar2010, 07:00 PM

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1. The problem statement, all variables and given/known data
If a man has an average useful power output of 41.4 W, what minimum time would it take him to lift fifty 15.0kg boxes to a height of 1.88 m? 2. Relevant equations 1/2mv(final)^2 mgy(final) = 1/2mv(initial)^2 mgy(initial) P=W/Δt P=Fv 3. The attempt at a solution Dont even know where to start 


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