# How to find the minium coefficient of static friction?

by ARJewell
Tags: coefficient, friction, minium, static
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 P: 6 1. The problem statement, all variables and given/known data For a system (with frictionless pulley) Mewsubk = .25 and the system is initially at rest. The mass of block 1 is 16 kg and the mass of block 2 is 12 kg. Determine the minimum coefficient of static friction needed to prevent any movement. 2. Relevant equations F=ma 3. The attempt at a solution I have no idea how to figure it out. I figured out the acceleration to be 2.8m/s^2 because: a= 12kg*9.8m/s^2 - .25*16kg*9.8m/s^2/(16kg+12kg) I figured out the tension in the connecting string to be 84 N because: T=mewsubk*m1g+m1a Any help on how to figure out minimum coefficient of static friction?
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Thanks
P: 26,148
Hi ARJewell ! Welcome to PF!

(have a mu: µ and try using the X2 tag just above the Reply box )
 Quote by ARJewell … Determine the minimum coefficient of static friction needed to prevent any movement. … F=ma
No, if movement is prevented (or even, in a different question, where the block is just moving), a must be zero!
Try again.

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