Find Wavelength of Light Through Slits

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Homework Help Overview

The discussion revolves around calculating the wavelength of light in a double slit experiment, where the distance between the first order bright lines and the slit separation are provided. Participants are attempting to apply the relevant formula for diffraction patterns.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the wavelength using a formula but expresses confusion about their result. Other participants clarify the variables involved in the formula for the double slit diffraction pattern.

Discussion Status

Some participants have provided clarifications regarding the definitions of the variables in the formula. The original poster acknowledges understanding after receiving input, indicating a potential shift towards resolution.

Contextual Notes

There is a mention of the specific distances involved in the setup, including the distance to the screen and the separation between the slits, which are crucial for applying the formula correctly. The original poster's initial misunderstanding of these variables is noted.

daisyi
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Almost done guys :)

If the first order bright lines formed by two slits at a distance of 2 meters are 3 cm apart, find the wavelength of the light if the slit separation is 9.12x10^-3 cm.

So, to find the wavelength, this is what I did.

wavelength = 9.12 * 10^-5m * (2m/(3*10^-2m)) = .00608m.

i'm not understanding what i am doing wrong. any input would be helpful. Thanks!
 
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You need to understand the formula for the double slit diffraction pattern. The distance of the first maxima (from the central maxima) is given by:
[tex]y = \frac{\lambda L}{d}[/tex]
 
Doc Al said:
[tex]y = \frac{\lambda L}{d}[/tex]


right, so y=9.12*10^-5m, d = 2m and L = 3*10^-2m.
 
daisyi said:
right, so y=9.12*10^-5m, d = 2m and L = 3*10^-2m.
Nope:
L is the distance to the screen
d is the distance between the slits
y is the distance of the first maxima to the center (this is half of the distance between those maxima).
 
thanks, i got it :)
 

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