
#1
Apr2210, 01:11 PM

P: 6

Hi, I'm not sure how to word my question, so I will just state it upfront.
What is the importance of [tex]\upsilon[/tex] = [tex]\sqrt{2gh}[/tex] in physics? I've seen it in escape velocity problems, though with an R instead of h. I've seen it with conservation of momentum applications, and it's similar to PE = mgh. Yesterday my professor was discussing Bernoulli's equation and this equation came up again. I was just wondering how it can be applied to so many different situations... 



#2
Apr2210, 04:52 PM

Sci Advisor
HW Helper
Thanks
P: 26,167

Hi acspin! Welcome to PF!
(have a squareroot: √ ) It's because v^{2} is KE per mass. Whenever KE + PE =constant, you'll have equations involving v^{2} = PE/m, which in some cases is gh. As to Bernouli's equation, that's just conservation of energy applied to a fluid, and both KE and PE appear in it. 



#3
Apr2310, 05:00 PM

P: 250

v^2=2ax. (where v at time t=0 is zero). 


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