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blablasometin
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A proton's speed as it passes point A is 53,000 m/s. It follows the trajectory shown in the figure below, in which V1 = 15 V and V3 = 5 V. What is the proton's speed at point B?
Figure: http://www.webassign.net/knight/p29-44alt.gif
Mass of proton: 1.67e-27
Charge of proton: 1.6e-19
Difference in Electric Potential
velocity at point A: 53000m/s
V1 = 15V
V2 = 10V
V3 = 5V
KE=1/2mv^2
V=(kq)/r
V=Ed
10q=1/2mv^2
v=sqrt(20*1.6e-19/1.67e-27)
Figure: http://www.webassign.net/knight/p29-44alt.gif
Homework Statement
Mass of proton: 1.67e-27
Charge of proton: 1.6e-19
Difference in Electric Potential
velocity at point A: 53000m/s
V1 = 15V
V2 = 10V
V3 = 5V
Homework Equations
KE=1/2mv^2
V=(kq)/r
V=Ed
The Attempt at a Solution
10q=1/2mv^2
v=sqrt(20*1.6e-19/1.67e-27)