# Electric Potential Vs. Electric Field

by pwkellysr
Tags: electric, field, potential
 HW Helper PF Gold P: 1,924 Hello pwkellysr, Welcome to Physics Forums! Yes, I think you are correct (if I'm understanding you correctly). Remember, potential is related to the definite integral of the electric field. $$V(B) - V(A) = -\int _A ^B \vec E \cdot d \vec l$$ I have a helpful hint. After almost forgetting it once and struggling miserably, I now repeat it myself almost every day. A definite integral is the area under the curve between two points. I'm sure you already know that. But really think about it. It's so easy to forget what it really means. In in your problem, plot E as a function of x. Well, between points A and B, E is a constant. But now plot the area under the curve from A to x. As x gets larger, so does the area! As you've already mentioned, $$\vec E = - \nabla V$$ And as you have correctly alluded, that's the same thing as saying the electric field has a constant magnitude, in regions where the electric potential has a constant slope.