Register to reply 
Charged particle in magentic field problem 
Share this thread: 
#1
May2710, 05:02 AM

P: 10

1. The problem statement, all variables and given/known data
A deuteron (the nucleus of an isotope of hydrogen) has a mass 3.34× 10−27 kg and a charge of +1.60 × 10−19 C. The deuteron travels in a circular path with a radius of 7.32mm in a magnetic field with magnitude 2.00T. (i) What is the angle between the velocity and magnetic field vectors? (ii) Calculate the speed of the deuteron. (iii) Calculate the time required for it to make half a revolution. 2. Relevant equations F=qVBsin(theta) R=(mv)/(qB) 3. The attempt at a solution I think I know how to solve parts ii and iii using the second equation listed, rearranged for V, then the time period would be ((pi)R)/V (half revolution) However with part i it seems to me there is no way of calculating the angle without knowing V? Am I missing something here? It seems stupid that they would ask for a calcualtion including V without working it out first, which comes after 


#2
May2710, 07:44 AM

HW Helper
Thanks
P: 10,344

What is the direction of the force the magnetic field exerts on the particle?
ehild 


#3
May2710, 08:01 AM

P: 10




#4
May2710, 08:36 AM

HW Helper
Thanks
P: 10,344

Charged particle in magentic field problem
Perfect. The force is the same as the centripetal force for the circular orbit the particle travels. This plane of the circle is perpendicular to the magnetic field. The velocity vector is in the same plane as the circle, is not it?
If the velocity of the particle were not perpendicular to the magnetic field, that is, it had both a parallel and normal component, the magnetic field would not influence the parallel component, the particle would move along a helix. ehild 


#5
May2710, 10:18 AM

P: 10




#6
May2710, 10:59 AM

HW Helper
Thanks
P: 10,344

What do you think? The particle moves in a plane that is perpendicular to the magnetic field. Can the velocity vector point out of this plane? What is the angle between any vector inplane and the magnetic field?
ehild 


#7
May2710, 11:16 AM

P: 10




#8
May2710, 01:42 PM

HW Helper
Thanks
P: 10,344

The particle moves along a circle with uniform speed. The circle defines the plane in which both the velocity and the force lie. The force is radial, and rotates around while the particle is moving. The magnetic field is perpendicular to the force at every instant: it is normal to the plane of the circle. The velocity also lies in the plane of the circle. If a vector is normal to a plane, it is perpendicular to every vector lying in the plane.
ehild 


#9
May2710, 02:35 PM

P: 10




#10
May2710, 05:43 PM

HW Helper
Thanks
P: 10,344

Well, one never knows who is there at the other end.
I suppose you know the answer to part i now? ehild 


#11
May2710, 06:23 PM

P: 10




#12
May2710, 11:22 PM

HW Helper
Thanks
P: 10,344

The circular orbit is crucial. If the particle had a component parallel with B, it would move along a helix. But it travels along a circle, so there is no parallel component of v.
ehild 


#13
May2810, 04:57 AM

P: 68

Drawing a picture might help a lot. I would highly recommend doing that if you haven't alreadly done it.



Register to reply 
Related Discussions  
Charged particle in a magnetic field  Introductory Physics Homework  2  
Charged particle in a magnetic field  Special & General Relativity  26  
Charged particle in magetic field problem  Introductory Physics Homework  4  
Charged Particle in Magnetic Field  Introductory Physics Homework  5  
Charged Particle in Magnetic Field  Advanced Physics Homework  2 