Conceptual Physics


by Dsoto489
Tags: conceptual, physics
proculation
proculation is offline
#73
May30-10, 11:18 PM
P: 71
Now 2
Attached Thumbnails
physics.jpg  
proculation
proculation is offline
#74
May30-10, 11:23 PM
P: 71
I guess if there are people watching this they are laughing haha.
Dsoto489
Dsoto489 is offline
#75
May30-10, 11:24 PM
P: 43
if i get a 0 in between the parentheses can i multiply it by 1/2
proculation
proculation is offline
#76
May30-10, 11:25 PM
P: 71
Quote Quote by Dsoto489 View Post
if i get a 0 in between the parentheses can i multiply it by 1/2
zero times 0.5 = zero.

That's why I corrected my mistake... I forgot the K of the integral
Dsoto489
Dsoto489 is offline
#77
May30-10, 11:26 PM
P: 43
sweet
Dsoto489
Dsoto489 is offline
#78
May30-10, 11:32 PM
P: 43
d=.06780672
Dsoto489
Dsoto489 is offline
#79
May30-10, 11:45 PM
P: 43
Thank you for the help, i will try again tomorrow.
proculation
proculation is offline
#80
May30-10, 11:46 PM
P: 71
AAh you really want me to get my pencils out to resolve that eh ? :P
Dsoto489
Dsoto489 is offline
#81
May31-10, 04:55 PM
P: 43
Ok! So after reworking the problem with different numbers this is what i did and the problem i needed to resolve:
A ball rolls off a shelf which is 2.8 meters high. If it leaves the shelf with a horizontal velocity of 6 m/s, calculate the distance from the base of the shelf at which the ball will strike the ground.

first i used Dvert=1/2at^2 so, 2.8=1/2 x 9.81 x t^2 solving for the time- the time it would take the ball to hit the floor. after square rooting it took aprox .75s to fall.

using Dhoriz=Vot D=6 x .75 the distance from the base at which the ball will strike the ground is 4.53m!

-There is only one other problem I am unable to resolve....

taking a trip you travel 63mph for 30 min, 22mph for 45 min and stop to eat for 20 min. What is your average speed for the entire trip?

what i keep doing is adding the speeds and averaging them, 63+22+0/3=28.33, this answer is wrong(the computer program for school i am using keeps telling me this) Total time is 95 min=1.55hours, i have tried several different ways and just do not get this problem(it seems easy though!)edit+ 85/1.55 =54.83

If you or someone could show me how to approach these types of problems dealing with different speeds over time that would be great. Thanks again proc!


Register to reply

Related Discussions
Q's regarding Conceptual Physics General Physics 16
Please help me, anyone! Conceptual physics Introductory Physics Homework 1
Conceptual Physics Introductory Physics Homework 4
Conceptual Physics Academic Guidance 3
Conceptual physics General Physics 24