Conceptual Physics

proculation

I corrected

(sorry i'm a little drunk, had problem with my integrals lol)

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Dsoto489

its cool,

with that drawing, the D of X is 4m methinks

proculation

damn forget that one too.

proculation

Now.

proculation

Now 2

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proculation

I guess if there are people watching this they are laughing haha.

Dsoto489

if i get a 0 in between the parentheses can i multiply it by 1/2

proculation

zero times 0.5 = zero.

That's why I corrected my mistake... I forgot the K of the integral

Dsoto489

sweet

Dsoto489

d=.06780672

Dsoto489

Thank you for the help, i will try again tomorrow.

proculation

AAh you really want me to get my pencils out to resolve that eh ? :P

Dsoto489

Ok! So after reworking the problem with different numbers this is what i did and the problem i needed to resolve:
A ball rolls off a shelf which is 2.8 meters high. If it leaves the shelf with a horizontal velocity of 6 m/s, calculate the distance from the base of the shelf at which the ball will strike the ground.

first i used Dvert=1/2at^2 so, 2.8=1/2 x 9.81 x t^2 solving for the time- the time it would take the ball to hit the floor. after square rooting it took aprox .75s to fall.

using Dhoriz=Vot D=6 x .75 the distance from the base at which the ball will strike the ground is 4.53m!

-There is only one other problem I am unable to resolve....

taking a trip you travel 63mph for 30 min, 22mph for 45 min and stop to eat for 20 min. What is your average speed for the entire trip?

what i keep doing is adding the speeds and averaging them, 63+22+0/3=28.33, this answer is wrong(the computer program for school i am using keeps telling me this) Total time is 95 min=1.55hours, i have tried several different ways and just do not get this problem(it seems easy though!)edit+ 85/1.55 =54.83

If you or someone could show me how to approach these types of problems dealing with different speeds over time that would be great. Thanks again proc!