# Rotary Piston

by emiltr
Tags: engine, piston, rotary
 P: 21 Thank you Jack,is useful and I have to study. Conclusion at first sight: the most efficiencies is bent axis motor. I think the rotary piston reaches at these performances. The main advantage is simplicity, reliability, low price.I also believe is more linear. His performance will not depend on pressure, rpm, vol. But we have made and put on a trial stand. Until there are no measurements can not say anything for sure. If I understood well,none is greater flow or high flow.Therefore, I asked the turbines. I think the rotary piston can give flow as turbines and efficiencies as reciprocating pumps. Rotary piston we can do very large.All movements are rotation.And there are only a few pieces.
 P: 21 I am confused, or I do not understand well. All I found on yield, yield is related to an ideal model.Says nothing about the ideal model. Where can I find an energy balance.Something like this: In a hydropower, energy consumption in time t, it is E1= Qght Q is flow , g is g-force,h is water height, t is time Energy loss is E2=QVVt / 2 V is water speed from outlet. Ceded power to the system is E1-E2. The yield is (E1-E2) / E1 X 100 Which generally is ...........Depends on water height as follows ........ For just a pump. Energy received on the shaft is ......,Amount of water pumped.........., from a height of ......, .... So energy is obtained .... The yield is ......
P: 578
 Quote by emiltr I am confused, or I do not understand well. All I found on yield, yield is related to an ideal model.Says nothing about the ideal model. Where can I find an energy balance.Something like this: In a hydropower, energy consumption in time t, it is E1= Qght Q is flow , g is g-force,h is water height, t is time Energy loss is E2=QVVt / 2 V is water speed from outlet. Ceded power to the system is E1-E2. The yield is (E1-E2) / E1 X 100 Which generally is ...........Depends on water height as follows ........ For just a pump. Energy received on the shaft is ......,Amount of water pumped.........., from a height of ......, .... So energy is obtained .... The yield is ......
Pump power calculator: http://www.engineeringtoolbox.com/pu...wer-d_505.html

Remember that the equivalent pressure P from a height h is:

$$P=\rho g h$$

So any pressure can be related to a "theoretical height".
P: 21
I think a specialist with the possibility of execution,should complete the "rotary piston", in weeks.I, alone, would take years.Too much!

A former colleague, mechanical engineer(sewing machine specialist), made the drawing of execution in 20 hours.I can not do.Execution on video you see is unacceptable.He said that to work correctly, must be designed by a specialist who has experience in pump design.

As I said, most importantly for me is to see running "rotary piston".That is,I will give everything I have.

I hope someone is interested and will signal back if he will have results.
Attached Files
 Gabarit.pdf (298.9 KB, 8 views) Executie.pdf (287.1 KB, 7 views)
 P: 21 Four-stroke engine has the following losses: 30% of energy is lost through cooling,40% is lost through the flue gas discharge and 8% mechanical losses and incomplete combustion.Only 32% of energy goes to the wheels.I try to eliminate these losses. The first step is to develop a compressed gas source having 5At.Little pressure to not need cooling and minimum loss due to exhaust gases. Put a burner in the chember, well insulated(burner as heating systems are or how are the water heaters).Mixture of intake are taken from a rotary pistonand and compressed in to combustion chamber.(This is the principle, I think the air will be compressed and the fuel will be injected).Burner burns all the time with different powers.When the pressure reaches 5At only the pilot flame burning. After burning gas volume multiply.Closed chamber, pressure and temperature increases.Chamber is not closed, the flow increases. Fuel can be anything that burns.Butan, alcohol, gasoline, oil, etc.. Burner must be dezigned for the fuel used. Until now, could not ensure efficient airflow ,needed for the combustion to 5At.Rotary piston can,also 5At were not sufficient to produce enough power.For rotary piston is enough. So,5At pressure is maintained with an automated system. A rotary piston is attached to the pressure at 5At. Rotary piston is usable area 100mm x 100mm = 10000mm = 100cm square square Force=5AtX100cm squar= 500Kgf = 5000N 200mm arm = 20cm ,torque results 5000 / 5 = 1000N / m High speed (20,000 rpm-30, 000rpm) and give a great power.We can have a lower rotary piston or a lower pressure The advantages of this engine are:reliability,lightweight,lower fuel consumption,low cost,easy maintenance. What is your opinion, PF

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