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Weight of man in a lift when lift is ascending/descending. |
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| Jun11-10, 02:14 AM | #1 |
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Weight of man in a lift when lift is ascending/descending.
I guess this is really basic physics to all of you but it got me thinking abit.
1. The problem statement, all variables and given/known data A man of mass 72kg tries to weigh himself in the lift using a weighing machine I am required to find his weight when the lift is stationary ,accelerating upwards(3m/s^2),travelling upwards at a constant speed(2m/s) and when the lift is accelerating downwards(4m/s^2) 2. Relevant equations W=mg F=ma 3. The attempt at a solution If i am not wrong, the weight of man when lift is stationary , W=mg = 72x10(at my level we don't require 9.81 yet) = 720N I got stuck when it came to accelerating up/downwards and moving at constant speeds cause I notice when I take the lifts down(descend) I seem to feel like something is pushing me upwards(g-force?) and when im taking the lift up I fee like something is pressing down on me. When the lift is coming to a halt I always feel a short sensation of weightlessness(well,a little) This got me to think that shouldn't the weight of the man fluctuate then when the lift is moving? If so,then there should be other forces causing the fluctuation. Can someone enlighten me on what other forces are acting? I'm guessing really small amounts of g-force,like when you jam the breaks in the car you come to a quick halt and you feel like something is pressing down on you(I assume it's the same feeling in F1 cars) Thanks in advance for anyone who would take time to clarify my doubts. :) |
| Jun11-10, 02:45 AM | #2 |
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You can count on other forces when you are in a non-inertial ,accelerated that is, frame of reference. These are pseudo forces and have no real existence. Weight of a man for us is actually the normal force that the floor of the lift would exert to balance other forces. Now if your observations are with respect to the earth you would agree that the man is accelerated. Apply the second law and calculate the normal force - that would be the apparent weight.
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| Jun11-10, 03:40 AM | #3 |
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| Jun11-10, 04:43 AM | #4 |
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Weight of man in a lift when lift is ascending/descending.
Since you haven't learned the non-inertial frame yet, I think the only way is to approach it in the reference frame of the earth (or the ground, the building, etc, as long as it's an inertial frame).
The "weight" the man experiences is actually the normal force N the floor exerts on him (note: this is what the man experiences). 1 - When you're at rest: N - mg = 0 2 - When you're accelerating upwards: N - mg = ma, so N = 72 x (10+3) = 936 N 3 - When you're traveling at constant speed: Since a=0, N - mg = 0. 4 - When you're accelerating downwards: mg - N = ma, so N = 72 x (10-4) = 432 N 2 - You seem to not understand the fictitious forces mentioned in wikipedia. I think you should forget what wiki tells you, because sometimes they mention some complicated concepts (such as relativity) which may confuse you, and wait for the next lesson in class or read the book at your level if you want. |
| Jun11-10, 05:04 AM | #5 |
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I get it now. Thanks for clarifying. Although not tested at my level,I will find out more about the concepts mentioned here that I did not really understand from my teacher. :) |
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