Christoffel symbol manipulation

by redstone
Tags: christoffel, manipulation, symbol
redstone is offline
Jul7-10, 08:10 PM
P: 26
1. The problem statement, all variables and given/known data
If the basic equation for the Christoffel symbol is
\Gamma^l_{ki} = \frac{1}{2} g^{lj} (\partial_k g_{ij} + \partial_i g_{jk} - \partial_j g_{ki})
so if you bring multiply the first metric into that equation, won't that turn the first two derivatives into derivatives of a mixed metric
\Gamma^l_{ki} = \frac{1}{2} (\partial_k g^{l}_{i} + \partial_i g^{l}_{k} - g^{lj} \partial_j g_{ki})
and then, wouldn't the first two terms go to zero, since they're just the derivative of the kronecker delta, which is constant? If that's correct, why not express the symbol instead as
\Gamma^l_{ki} = \frac{1}{2} ( - g^{lj} \partial_j g_{ki})
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Dick is offline
Jul7-10, 09:50 PM
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Because g^{lj}*partial_k(g_{ij}) is not generally equal to partial_k(g^{lj}*g_{ij})=0. The metric components are not generally constants. Use the product rule on the second expression.
redstone is offline
Jul11-10, 06:48 PM
P: 26
oh, jeez, of course. I feel silly now.

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