Help with Mechanics: Towing a Barge with Flexible Cable

  • Thread starter Thread starter teru
  • Start date Start date
  • Tags Tags
    Hard Mechanics
Click For Summary
SUMMARY

The discussion focuses on the mechanics of a tugboat towing a barge using a flexible cable, specifically analyzing the effects of decreasing thrust on the system. The tugboat has a mass of 10,000 kg and the barge has a mass of 100,000 kg, with drag characteristics defined as D1 = 2000(v1)^2 N for the tugboat and D2 = 6700(v2)^2 N for the barge. The key challenge is to determine the maximum rate of decrease of thrust (dT/dt) that maintains tension in the cable during deceleration to a barge velocity of 0.4904 m/s. Additionally, the discussion confirms that the non-linear differential equations governing the system can be solved numerically using methods such as Euler's or Runge-Kutta.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with drag force equations
  • Knowledge of numerical methods for solving differential equations
  • Basic concepts of tension in flexible cables
NEXT STEPS
  • Study the application of Newton's second law in multi-body systems
  • Learn about drag force calculations in fluid dynamics
  • Explore numerical methods for solving ordinary differential equations, focusing on Euler's method and Runge-Kutta method
  • Investigate the effects of cable stiffness on tension and system dynamics
USEFUL FOR

Students and professionals in physics, mechanical engineering, and maritime operations who are dealing with dynamics involving towing systems and flexible cables.

teru
Messages
2
Reaction score
0
mechanics is hard...need help!

hello physics forums,
this is lengthy but pretty much challenging..really appreciate any help ^o^

A tugboat is towing a barge with a flexible cable. After towing steadily at constant speed for sometime, the tug propeller thrust T(t) is decreased from 100kN at a steady rate (dT/dt = constant).

given: mass of tug, m1 = 10,000 kg
mass of barge, m2 = 100,000 kg
tug drag characteristic, D1 = 2000.(v1)^2 N
barge drag charateristic, D2 = 6700.(v2)^2 N
cable stiffness 800 kN/m
vb = 0.4904 m/s

1) Determine the maximum magnitude of the 'steady rate' that ensures the tow cable is always in tension during the deceleration from the constant speed to a barge velocity, vb m/s (ignore the cable mass and its sag).

2) Can the non-linear differential equations be solved numerically. how will v1 and v2 behave with respect to time, t?
 
Last edited:
Physics news on Phys.org
1) I'm not sure how "cable stiffness" affects this but:
Let F be the tension in the cable. There are three forces on the tugboat: the thrust from its propellor, T, which is positive, the drag, which is negative, and the pull from the barge, F, which is negative: [itex]10000\frac{dv_1}{dt}= T- 2000v_1^2-F[/itex].
There are two forces on the barge, the pull from the tugboat, F, which is positive, and the drag, 6700 v22, which is negative: [itex]100000\frac{dv_2}{dt}= F- 6700v_2^2[/itex].

Question 1 asks, what is the maximum of dT/dt so that F never becomes 0.
 


Hi there,

I understand that mechanics can be challenging, but with some guidance and practice, I believe you can master it! Let's break down the problem and see how we can approach it.

First, let's draw a free body diagram of the system. We have the tugboat and barge connected by a flexible cable, and we also have the forces acting on each object (thrust, drag, and tension in the cable).

Next, we can apply Newton's second law to each object to set up the equations of motion. We know that the tugboat and barge are moving at a constant speed, so the sum of the forces in the x-direction must be equal to zero. This allows us to solve for the tension in the cable, which should always be in tension to keep the objects connected.

Now, we can use the given drag characteristics to solve for the drag forces on each object. From there, we can set up an equation for the acceleration of the system, which will depend on the rate at which the thrust is decreased.

To ensure that the cable is always in tension during the deceleration, we need to find the maximum magnitude of the steady rate (dT/dt) that will not cause the tension to become zero. We can set up an inequality using our equation for acceleration and the maximum tension we found earlier.

As for the second part of the problem, yes, the non-linear differential equations can be solved numerically. You can use numerical methods such as Euler's method or Runge-Kutta method to solve for the velocities of the tugboat and barge with respect to time. The behavior of v1 and v2 will depend on the initial conditions and the rate at which the thrust is decreased.

I hope this helps you get started on the problem. Remember to always draw a free body diagram and apply Newton's laws to solve mechanics problems. Good luck!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
2
Views
8K
  • · Replies 36 ·
2
Replies
36
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
11K