Register to reply 
Escape Velocity Formula 
Share this thread: 
#1
Sep504, 09:19 PM

Sci Advisor
PF Gold
P: 1,542

Let's say I have an object orbiting the Sun in a circular orbit with an orbital velocity of 30 km/s. If I want to accelerate prograde into a hyperbolic orbit, and I'd like my velocity relative to the Sun to be 1 km/s at infinity, what is the formula I'd use to figure out how much delta v in the prograde direction I'd have to apply? I believe the formula for escape velocity is [itex]circular velocity * sqrt{2}[/itex], but I want to know how much further I must accelerate to have 1 km/s of extra velocity when the rocket has distanced itself from the Sun.
Also, how do I get the root symbol in the tex tags? 


#2
Sep504, 10:27 PM

Emeritus
Sci Advisor
PF Gold
P: 2,361

You would have to accelerate 1 km/sec more.
The root function for squareroot is \sqrt{n} the radical sign will be placed over n like this: [tex]\sqrt{2}[/tex] or [tex]\sqrt{\frac{2GM}{R}}[/tex] 


#3
Sep504, 10:28 PM

Sci Advisor
PF Gold
P: 1,542

Never mind... I figured it out.
[tex]vescape = \sqrt{2}*vcircular[/tex] [tex]vrequired = \sqrt{vescape^2 + vinfinity^2}[/tex] edit... to change to TEX format. I love these TEX things. Thanks Janus. 


#4
Sep504, 10:30 PM

Sci Advisor
PF Gold
P: 1,542

Escape Velocity Formula
That was my original guess, but it didn't work. The formula in the above post works though. Thanks, Janus. BTW... Is your name in reference to Saturn's moon? That's a cool moon as it shares a horseshoe orbit with Epimetheus. 


Register to reply 
Related Discussions  
Escape velocity  Introductory Physics Homework  1  
Escape Velocity  Introductory Physics Homework  4  
'escape' velocity  General Physics  15  
Escape Velocity  Introductory Physics Homework  3  
Escape velocity  Classical Physics  16 