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Work to move charges from Infinity to origin |
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| Aug15-10, 02:03 AM | #1 |
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Work to move charges from Infinity to origin
1. The problem statement, all variables and given/known data
Eight 3.0 μC charges are located at the corners of a unit cube centered about the origin with 1mm edges. How much work does it take to bring a 5.0 μC charge from infinity to the origin? 2. Relevant equations U= k*q1*q2/r 3. The attempt at a solution r= ((1*10^-3)^2+(1*10^-3)^2+(1*10^-3)^2))^(1/2)m =1.73*10^-3m U=(9*10^9)*(3*10^-6)*(5*10^-6)*8 / (1.73*10^-3) =623.54 J U at Infinite = 0 Work = 623.54 J I have tried to explain why I have simply multiplied one result by 8 below. The charge will have to have some path to get to the center of the cube and as a result there will be some time where it will be closer to some charges(a) than 1.73*10^-3m which would require more work to move the charge(b) closer than this. This extra work will be counter-acted as there will be negative work equal to this for the charge(b) to move away from the charge(a) once again. Ok so this is the answer that I have obtained, unfortunately this is not one of the multiple choice options available. So I am not confident that I have completed the problem correctly, any feedback would be most welcomed. |
| Aug15-10, 02:31 AM | #2 |
Recognitions:
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The cube is centered about the origin. How far is the centre of a cube from the corners?
ehild |
| Aug15-10, 03:36 AM | #3 |
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Eight 3.0 μC charges are located at the corners of a "unit cube centered about the origin with 1mm edges"
r= ((1*10^-3)^2+(1*10^-3)^2+(1*10^-3)^2))^(1/2)m =1.73*10^-3m Wouldn't that be the distance? |
| Aug15-10, 04:04 AM | #4 |
Recognitions:
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Work to move charges from Infinity to origin
No. Make a picture. What does it mean "centered about the origin? "
ehild |
| Aug15-10, 04:13 AM | #5 |
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Ok I think I have seen where I have made the mistake, thank you for your 'guidance' :)
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