What is the reflection coefficient on a transmission line at a resistor halfway?


by Rib5
Tags: coefficient, halfway, line, reflection, resistor, transmission
Rib5
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#1
Aug31-10, 07:24 PM
P: 56
1. The problem statement, all variables and given/known data
If I have a coaxial transmission line, with a resistor halfway through, and another resistor at the end, how do I calculate the reflection coefficient for the spot where the resistor is halfway?

Here is a diagram of what I mean. Dashes and dots are are the lines, and } are resistors.

----------
....}a....}b



2. Relevant equations
[tex]\Gamma_{L} = \frac{Z_L-Z_o}{Z_L+Z_o}[/tex]


3. The attempt at a solution
I am pretty sure the formula I am supposed to use is [tex]\Gamma_L = \frac{Z_L-Z_o}{Z_L+Z_o}[/tex]. What I am not sure is what value to choose for [tex]Z_L[/tex]. Do I take [tex]Z_o[/tex] in parallel with [tex]R_A[/tex]?
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xcvxcvvc
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#2
Aug31-10, 08:23 PM
P: 393
you know how you can take any length of transmission line plus an impedance at the end, and transform it into a single impedance that the source sees?

Well, put your finger over resistor a and the rest of the circuit, and apply that formula to transform your circuit from
L/2 of wire-> impedance a -> L/2 of wire -> impedance b
into
L/2 of wire -> impedance a -> equivalent impedance B

you need to use the length L/2, not L, when you calculate the equivalent impedance for resistor b, because you're calculating the equivalent impedance that resistor a sees. Next, now that resistor behaves just like they do in your circuits class. Take equiv b in parallel with a (assuming a branches across and connects the wires) to find a single impedance at the "end of the wire" (which represents what impedance is seen at the halfway point). Then apply your reflection equation.


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