
#1
Sep710, 11:32 PM

P: 140

I'm trying to negate this statement and wanna make sure I'm doing it right.
(p[tex]\vee[/tex]q) > (p [tex]\wedge[/tex] q) So I dont negate both sides do I or else that would just make them equal out again? So I just negated the left side, so [tex]\neg[/tex](p[tex]\vee[/tex]q) is equivalent to [tex]\neg[/tex]p[tex]\wedge[/tex][tex]\neg[/tex]q So thats the answer I got: [tex]\neg[/tex]p[tex]\wedge[/tex][tex]\neg[/tex]q > (p [tex]\wedge[/tex] q) 



#2
Sep810, 12:05 AM

P: 617

p=>q = ~p or q
Using de morgans law : ~(p=>q) = ~(~p or q) = p and ~q So ~(p or q implies p and q) = p or q and ~(q and p) > p or q and ~q or ~p > p xor q 



#3
Sep810, 01:24 AM

P: 140

Sorry Im new to all this and what you have up there is very confusing. I cant really tell whats going on and what the final answer is. Anyway you can use the actual math symbols and break the steps into separate lines? I'd really appreciate it :)




#4
Sep810, 05:30 AM

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Logic: Negating if then statement
JonF's already done too much work for you. It's against the forum rules to simply do the problems for you. You're supposed to work them out yourself.
Use the fact that you can write p→q as (~p)∨q. The latter form is easier to see how to negate. 



#5
Sep810, 01:24 PM

P: 140

Ya you're right sorry..I was just having a hard time understanding the symbols he was using but I think I got it now..so the final answer I got was:
(p v q) ^ (~p v ~q) Is this what you had? 



#6
Sep810, 01:52 PM

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That's correct. You can simplify it a bit if you want.



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