| Thread Closed |
Interpreting the Supernova Data |
Share Thread |
| Sep12-10, 07:16 PM | #52 |
|
|
Interpreting the Supernova Data |
| Sep12-10, 07:21 PM | #53 |
|
Recognitions:
|
These values are typically listed for each supernova when a supernova experiment's results are reported. For instance, here is the SNLS first-year release: http://xxx.lanl.gov/abs/astro-ph/0510447 The table including the supernovae is at the end. The redshift of each supernova is measured by careful measurement of its spectrum. The magnitudes of each supernova are also listed, and the relationship to the luminosity distance is described in the paper. Look, you can't just say, "Hey, look, in this model the words I use make it sound sort of like it works like this other model! Therefore they're the same!" This isn't the way science works. You have to dig into the details of the model and see what it actually says, not just look at superficial behavior. |
| Sep12-10, 07:29 PM | #54 |
|
|
In the case that you have a model with these six parameters, then I have to admit that is more interesting. |
| Sep12-10, 07:59 PM | #55 |
|
Recognitions:
|
http://space.mit.edu/home/tegmark/cmb/movies.html Note that these animations were made before WMAP, and the data on the plot is a combination of pre-WMAP data. He also adds the effects of a couple of extra parameters that are not in the simplest-case analysis, so you can see what they do. |
| Sep12-10, 09:38 PM | #56 |
|
|
You can do the same calculation with the Milne model. People have done that calculation and you get nowhere near the observed universe. |
| Sep12-10, 09:46 PM | #57 |
|
|
The easily analogy is that you can draw a diagram with square graph paper, or you can draw the diagram with polar coordinates. It's all the same. |
| Sep12-10, 09:53 PM | #58 |
|
|
|
| Sep13-10, 05:32 AM | #59 |
|
|
When I apply this transformation to the minkowski metric:
[tex] r \to t \sinh r [/tex] [tex] t \to t \cosh r [/tex] I don't get this [tex]ds^2 = dt^2-t^2(dr^2+\sinh^2{r} d\Omega^2)\ [/tex] But this [tex]ds^2 = dt^2-t^2(\sinh^2{r} d\Omega^2)\ [/tex] I lose the dr^2 term, what am I doing wrong? |
| Sep13-10, 05:39 AM | #60 |
|
Recognitions:
|
|
| Sep13-10, 06:42 AM | #61 |
|
|
From the Minkowski metric with this coordinate transform
[tex] r \to t \sinh r [/tex] [tex] t \to t \cosh r [/tex] Here's what I get since: [tex]\cosh^2{r}-\sinh^2{r}=1[/tex] [tex]ds^2 = dt^2\cosh^2{r}-dt^2\sinh^2{r}-t^2\sinh^2{r} d\Omega^2 =dt^2(\cosh^2{r}-\sinh^2{r})-t^2\sinh^2{r} d\Omega^2=dt^2-t^2(\sinh^2{r} d\Omega^2)[/tex]
|
| Sep13-10, 06:52 AM | #62 |
|
Recognitions:
|
[tex]r \to t \sinh r[/tex] Leads to: [tex]dr \to \sinh r dt + t \cosh r dr[/tex] I'm sure you can figure out the rest. |
| Sep13-10, 07:00 AM | #63 |
|
|
Thanks |
| Sep13-10, 07:03 AM | #64 |
|
Recognitions:
|
|
| Sep13-10, 03:41 PM | #65 |
|
|
[tex]\begin {matrix} z=r cos \theta \\ x=r sin \theta cos \phi\\ y=r sin \theta sin \phi \end {matrix} [/tex] This is something true about the mathematical relationships between the radius, the polar angle, and the azimuthal angle. In Special Relativity, also, you can perform the coordinate transformation: [tex] \begin{bmatrix} c t' \\ x' \end{bmatrix} = \begin{bmatrix} \cosh\phi &-\sinh\phi \\ -\sinh\phi & \cosh\phi \\ \end{bmatrix} \begin{bmatrix} c t \\ x \end{bmatrix} [/tex] This is also okay, because on the left hand side, we have t' and x'. These are the coordinates of events in another inertial reference frame. t' and x' are fundamentally different from t and x, so it is okay that they have different forms. (You cannot, by the way, say "you want a ruler that shrinks as you move it." or "you want a clock that speeds up or slows down." There are explicit relationships that are already determined.) Mapping from [itex](x,y,z) \to (r,\theta,\phi)[/itex] or [itex](x,t) \to (x',t')[/itex] is mathematically and physically valid. However, when you say: [tex] \begin {matrix} t\to t \cosh r\\ r \to t \sinh r \end {matrix} [/tex] You are replacing distance with distance, and time with time. Certainly, you preserve all of the information by doing so, but you do not preserve the shape. For instance: all of the following represent coordinate transformations of the earth. a) http://en.wikipedia.org/wiki/Peters_map b) http://en.wikipedia.org/wiki/Albers_projection c) http://en.wikipedia.org/wiki/Mercator_projection d) http://en.wikipedia.org/wiki/Globe Three of these transformations significantly affect the shape of the earth, while the fourth only affects the size and position. The globe represents the true shape, and the others represent convenient distortions of the shape depending on the purpose.. However, they still do not actually map [itex](x,y,z) \to (x,y,z)[/itex]. If you would like to claim: [tex] \begin {matrix} t' \to t \cosh r\\ r' \to t \sinh r \end {matrix} [/tex] ...then I can ask you why you think this is a convenient distortion of the shape, and what was your purpose in making that distortion. But to claim [tex] \begin {matrix} t\to t \cosh r\\ r \to t \sinh r \end {matrix} [/tex] ... is to claim that t is mathematically different than t, and r is mathematically different from r. This is not legitimate. Milne, by the way, was also quite disturbed at Eddington's "scale factors" and spent quite some effort in pointing out how ridiculous it was. If Milne knew that a model named after him had been saddled with such a thing, I think he would roll over in his grave. |
| Sep13-10, 09:02 PM | #66 |
|
Recognitions:
|
Your resistance to this coordinate change is truly amusing. It is possible in General Relativity to make any coordinate transformation at all, provided the coordinate transformation is one-to-one in some region. That is, the only limitation opposed on coordinate transformations is that they don't throw away information.
As long as your coordinate transformation satisfies this, any calculation you might ever do regarding a physical observable will give the same answer. The use of different systems of coordinates is merely a mathematical convenience of no physical meaning whatsoever. The real world, after all, doesn't have numbers written on it. |
| Sep14-10, 06:10 AM | #67 |
|
|
I have no resistance to saying [tex] \begin {matrix} t' \to t \cosh r\\ r' \to t \sinh r \end {matrix} [/tex] ...if you can explain what you mean by t, t', r, r'. But, what you are claiming, is: [tex] \begin {matrix} t \to t \cosh r\\ r \to t \sinh r \end {matrix} [/tex] This is nonsense, and it certainly wasn't what Milne ever meant. |
| Sep14-10, 07:29 AM | #68 |
|
Recognitions:
|
|
| Thread Closed |
| Tags |
| big bang, inflation, metric, milne, supernova |
Similar discussions for: Interpreting the Supernova Data
|
||||
| Thread | Forum | Replies | ||
| Process of interpreting experimental data | Astrophysics | 0 | ||
| Integration of acceleration signal response data to obtain displacement rseponse data | Differential Geometry | 0 | ||
| Graphically interpreting data regarding magnification with a convex lens | Introductory Physics Homework | 1 | ||
| Does 1a supernova release the same amount of neutrino as type2 supernova? | Astrophysics | 1 | ||
| Estimating a neutrino mass upper limit from supernova data | Introductory Physics Homework | 0 | ||