Solve 2.00 & 4.60µF Capacitors Voltage: Help Needed

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The discussion focuses on calculating the final voltage across two capacitors, a 2.00 µF capacitor charged to 520 V and a 4.60 µF capacitor charged to 570 V, when connected in series with opposite polarities. The relevant formula is C=Q/V, where C is capacitance, Q is charge, and V is voltage. The final voltage can be determined by first calculating the charge on each capacitor and then using the total charge to find the resulting voltage across the combined capacitance.

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Here is the question

A(n) 2.00 µF capacitor is charged to 520 V and a 4.60 µF capacitor is charged to 570 V

What is the voltage for each capacitor if plates of opposite signs are connected?

Any help would be helpful. I have bene trying to get this and haven't been able to all night. I only have one submission left to get the right answer soany suggestions would be greatly appreciated.
 
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The equation is C=Q/V. Just by pluggin in values does not work for me and i can't figure out what I am supposed to do.
 
I still can't figure it out. I have been trying and still can't get the right answer. I have an answer similar for a question for 2.4uF and 880V and 4uF and 560V capacitors. The voltage is 20V for that one. I can't even get that answer
 

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