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Deriving the potential from the propagator

by 1Kris
Tags: deriving, potential, propagator
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1Kris
#1
Sep24-10, 10:47 AM
P: 22
I've read that the form of the potential field can be derived from the propagator for the virtual particles of that field. As far as I can see the potential is equal to the Fourier transform of the propagator. Is this true? / Why is this so?
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