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Einstein Field Equations??? |
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| Nov8-10, 06:06 PM | #52 |
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Einstein Field Equations???http://www.mathpages.com/rr/s6-03/6-03.htm has a pretty good, if somewhat brief, discussion. Edit: I should also note that I was using language loosely in referring to the "Newtonian" part of the bending of light as "space curvature" and the rest as "time curvature". The full general relativistic deflection is what will show up in any measurements, even if they are "purely spatial" in nature. For example, suppose we sent two satellites out and positioned them in such a way that they could send out laser pulses to Earth that would appear to come from opposite sides of the Sun and just grazing the Sun's surface. If we then measured the three angles of the triangle formed by the two pulses and a third pulse sent between the satellites at the same time as the first two pulses were emitted (we assume that this third pulse's path is far enough away from the Sun that any relativistic effects on the path due to the Sun's gravity are unmeasurable), we would find that the sum of the angles was larger than 180 degrees by the full GR deflection amount, summed for both laser pulses. |
| Nov8-10, 07:04 PM | #53 |
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| Nov8-10, 07:13 PM | #54 |
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Edit: I should also note that I remember reading in at least some sources (as I noted in an earlier post, I haven't had time to check references for specific quotes) that the existence of the Shapiro time delay is the reason for attributing the fact that the GR result for the angle of light bending is twice the Newtonian one to the presence of "time curvature" as well as "space curvature" (hence the 50-50 split). However, as I said, I agree that's a loose use of language. |
| Nov8-10, 07:42 PM | #55 |
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http://einstein.stanford.edu/SPACETIME/spacetime3.html This has the following quote in the section on light bending by the Sun: |
| Nov8-10, 07:55 PM | #56 |
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For starters in light bending calculations the r coordinate is actually used as a physical distance so spatially speaking there is not much going on as space is now assumed spatially flat (e.g. rho is assumed equal to r). On the other hand light actually decelerates when attracted by a gravitational field and my intuition would say that is the reason for the 'double whammy' not spatial curvature. Surely I must be wrong, for my understanding is little, and greater minds on this website will obviously have no trouble at all to demonstrate I am wrong and lack understanding by using the appropriate formulas. So I remain. |
| Nov8-10, 08:10 PM | #57 |
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| Nov10-10, 12:20 PM | #58 |
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http://www.physicsforums.com/showthread.php?t=446589 |
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