Find the magnitude of the trucks horizontal component of displacement

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SUMMARY

The discussion focuses on calculating the horizontal component of displacement for a truck traveling 1270 meters uphill at an angle of 4.45 degrees. The horizontal component can be determined using trigonometric functions, specifically the cosine function. The calculation yields a horizontal displacement of approximately 1270 * cos(4.45°), which results in a value of about 1265.5 meters. Additionally, the vertical component can be calculated using the sine function.

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  • Understanding of basic trigonometry, including sine and cosine functions.
  • Familiarity with vector components and displacement calculations.
  • Ability to convert between units (meters and kilometers).
  • Knowledge of angles in degrees and their application in real-world scenarios.
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kimikims
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Can anyone help me with these 2 problems.. I have been stuck on them

Thanks!

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A car travels 1.14km in the x- direction, then turns left 74.1 degrees to the original direction and travels an additional distance of 3.18km. Calculate the x component of the car's net displacement. Answer in units of km.

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A truck travels 1270m uphill along a road that makes a constant angle of 4.45 degrees with the horizontal.

1) Find the magnitude of the trucks horizontal component of displacement. Answer in units of m.

2) Find the magnitude of the trucks veritical component of displacement. Answer in units of m.
 
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Draw a picture of the situation and add the given data (angles and distances).
Then use trigonometry. (You know, with triangles and stuff).
 

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